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DiKsa [7]
3 years ago
12

During a solar flare, it is most likely that (3 points)

Physics
2 answers:
Y_Kistochka [10]3 years ago
8 0

Answer:

the aurora borealis will be seen in the night sky

Explanation:

I think so..

professor190 [17]3 years ago
5 0

Answer:

During a solar flare a electrical power will be generated on earth

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Light year is light in a year so 4 light years are 4 Earth years
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What is the acceleration of the object at t = 4s?
kolbaska11 [484]

Answer:

no answer of this bcuz to find aclleration.initial velocity and final velocity too... I think question is wrong

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3 years ago
What do astronomers expect will eventually happen to the Milky Way galaxy?
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<span> The Andromeda Milkyway is a galactic collision predicted to occur in 4 billion years. I believe thats the answer</span>
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3 years ago
Read 2 more answers
A large box has a mass of 500kg and the coefficient of static friction for the box and the floor is 0.45, and the coefficient of
Mumz [18]
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.

b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight). 

F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N

a = (735.75 N)/(500kg)= 1.4715 m/s^2
4 0
3 years ago
A kid throws a ball from a tower 45 meters tall how fast is the ball going when it hits the ground?
IRISSAK [1]

Answer:

29.69 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) = 45 m

Velocity (v) =...?

Next, we shall determine the time taken for the ball to get to the ground. This can be obtained as follow:

Height (h) = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.9 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the velocity with which the ball hits the ground. This is illustrated below:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 3.03 s

Final velocity (v) =.?

v = u + gt

v = 0 + (9.8 × 3.03)

v = 0 + 29.694

v = 29.694 ≈ 29.69 m/s

Therefore, the ball hits the ground with a velocity of 29.69 m/s.

8 0
4 years ago
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