Light year is light in a year so 4 light years are 4 Earth years
Answer:
no answer of this bcuz to find aclleration.initial velocity and final velocity too... I think question is wrong
<span> The Andromeda Milkyway is a galactic collision predicted to occur in 4 billion years. I believe thats the answer</span>
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.
b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight).
F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N
a = (735.75 N)/(500kg)= 1.4715 m/s^2
Answer:
29.69 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) = 45 m
Velocity (v) =...?
Next, we shall determine the time taken for the ball to get to the ground. This can be obtained as follow:
Height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
45 = ½ × 9.8 × t²
45 = 4.9 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the velocity with which the ball hits the ground. This is illustrated below:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 3.03 s
Final velocity (v) =.?
v = u + gt
v = 0 + (9.8 × 3.03)
v = 0 + 29.694
v = 29.694 ≈ 29.69 m/s
Therefore, the ball hits the ground with a velocity of 29.69 m/s.
