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faust18 [17]
3 years ago
15

Grasses living in an area have shallow but widespread roots that grab

Chemistry
1 answer:
Sophie [7]3 years ago
4 0
The answer is C I hope
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Estimate the solubility of m(oh)2 in a solution buffered at ph = 7.0, 10.0, and 14.0.
kherson [118]
<span>When M(OH)2 dissolves we have M(OH)2 which produces M2+ and 2OHâ’ pH + pOH=14 At ph =7; we have 7+pOH=14 pOH=14â’7 = 7 Then [OHâ’]=10^(â’pOH) [OH-] = 10^(-7) = 1* 10^(-7) At ph = 10. We have, pOH = 4. And [OH-] = 10^(-4) = 1 * 10^(-4) Finally ph = 14. We have, pOH = 0 And then [OH-] = 10^(-0) -----anything raised to zero power is 1, but (-0)... So [OH-] = 1</span>
4 0
3 years ago
A _____ change occurs when a substance changes phase. physical chemical nuclear user: the latent heat of vaporization of ethanol
dezoksy [38]
<span> physical 

</span><span>about 200 calories of heat must be added to 1 gram of ethanol to convert it from a liquid to a gas</span><span>






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3 0
3 years ago
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Which planet is the most massive? A.Jupiter B.Mercury C.Venus D.Neptune
Ainat [17]

Jupiter is the biggest planet in are solar system

7 0
3 years ago
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train travel from hong kong to beijing it traveled at an average speed of 160 km/m in the first 4 hours. after that it traveled
Nonamiya [84]

Answer:

7 hours

Explanation: step 1. 160x4=640

step 2. 1180-640=540

step 3. 540÷180=3

step 4. 3+4=7

5 0
3 years ago
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For the following electrochemical reaction: Al3+(aq) + 3e -&gt; Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -&gt; 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
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