Answer:
![[SO_2Cl_2]=0.0175M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0175M)
Explanation:
Hello!
In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:
![r=-k[SO_2Cl_2]](https://tex.z-dn.net/?f=r%3D-k%5BSO_2Cl_2%5D)
We also consider that the integrated rate law has been already reported as:
![[SO_2Cl_2]=[SO_2Cl_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D%5BSO_2Cl_2%5D_0exp%28-kt%29)
Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:
![[SO_2Cl_2]=0.0225Mexp(-2.90x10^{-4}s^{-1}*865s)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0225Mexp%28-2.90x10%5E%7B-4%7Ds%5E%7B-1%7D%2A865s%29)
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D. I or Iodine
This is because they are both in the same periodic family (the halogens) and thus the number of valence electrons are the same
Answer:
The correct answer is due to the difference in pressure inside and outside the bottle.
Explanation:
Liquids have melting and boiling points that depend on pressure and temperature. The pressure inside the bottle is higher than the pressure outside. This causes the melting point to drop, making the liquid freeze at a lower temperature than if it were at atmospheric pressure, and therefore has a lower temperature than it would freeze at atmospheric pressure. When the bottle is uncovered, the liquid becomes an atmospheric pressure, and due to the temperature acquired when the bottle was closed the liquid freezes.
Have a nice day!
PH of solution will be greater than seven (pH>7), that means that solution is basic (<span>pH above </span>7<span> is a base, the higher the number, the stronger is the base).
</span>pH (potential of hydrogenis) is a measure of the hydrogen ion (H⁺) concentration of a solution. <span>Solutions with a pH less than 7 are acidic.</span>
Answer:
-133.2 kJ
Explanation:
Let's consider the following balanced equation.
4 KClO₃(s) → 3 KClO₄(s) + KCl(s)
We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.
ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))
ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)
ΔG°rxn = -133.2 kJ
