Someone please help me with this math question

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astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago

A classmate said that AB & DC are complementary and parallel based on the diagram below. Explain your classmate's error. Not

Ugo [173]

Your classmate's error about AB and DC being complimentary and parallel is that they misapplied the alternate angle property.

<h3>Why are AB and DC not parallel?</h3><h3 />

There isn't enough evidence presented in the diagram to say that AB and DC are parallel.

The evidence required would be proof that angle AWZ is equal to angle WZY.

Instead, all we have is that angle AWZ and angle XYC are equal which does not tell us what we need to know about AB and DC being parallel.

Find out more on properties of parallel lines at brainly.com/question/24607467

#SPJ1

3 0

9 months ago

BRAINLIEST ANSWER FAST!Subtract and simplify. Show work to earn full credit.

Alecsey [184]

Answer:

Step-by-step explanation:

(-2y^2-11y-7)-(-9y^2-5y+10) (firstly, we remove the brackets)

-2y^2 - 11y - 7 + 9y^2 + 5y - 10

= (-2y^2 + 9y^2) + (-11y + 5y) + (-7 - 10)

= (7y²) + (-6y) + (-17)

7 0

3 years ago

What is the solution <br> 2 – 3y=1<br> x – 2y = 6

slava [35]

Answer: x = - 16

y = - 11

Step-by-step explanation:

The given system of linear equations is expressed as

2x - 3y = 1- - - - - - - - - - - - -1

x - 2y = 6 - - - - - - - - - - - -2

We would eliminate x by multiplying equation 1 by 1 and equation 2 by 2. It becomes

2x - 3y = 1- - - - - - - - - - -3

2x - 4y = 12- - - - - - - - - - - -4

Subtracting equation 4 from equation 3, it becomes

y = - 11

Substituting y = - 11 into equation 2, it becomes

x - 2 × - 11 = 6

x + 22 = 6

Subtracting 22 from the left hand side and the right hand side of the equation, it becomes

x + 22 - 22 = 6 - 22

x = - 16

6 0

3 years ago

Write in slope intercept form an equation of the line that passes through the points (-5,6) and (3,10)

lisov135 [29]

Answer:

y= 1/2x + 17/2

Step-by-step explanation:

First, find your slope using y-y1/x-x1. This is your expression: 10-6/3--5. 10-6 equals 4, and 3--5 equals 8. Your slope is 4/8, but it can be simplified to 1/2. This should be your current equation: y=1/2x+b. Plug in one of your ordered pairs to the equation, it doesn't matter which pair you want to use. I'm using the second ordered pair, so this is what you would have: 10=1/2(3)+b. Multiply 1/2 by 3 to get 3/2. This is what it should look like: 10=3/2+b. Subtract 3/2 from both sides to get your y-intercept of 17/2. Go back to your original equation and plug in your y-intercept. This is your final answer: y= 1/2x + 17/2. Hope this helped!

5 0

3 years ago