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3 years ago

Someone please help me with this math question

Mathematics

1 answer:

Molodets [167]3 years ago

5 0

Answer:

3rd one

Step-by-step explanation:

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An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

3 years ago

A box measures 20 inches wide by 14 inches deep. The height of the box is two feet. What is the volume of the box? Remember two

Jobisdone [24]

Answer:

6,720 inches or 560 feet

Step-by-step explanation:

20 x 14 x 24 = said number above.

Remember volume is just length times width times height.

8 0

3 years ago

Jane took 15 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat

s344n2d4d5 [400]

Answer:

The speed of the boat in still water = 8 Km/hr

Step-by-step explanation:

Let the speed of the boat be x

According to question

(x-4)15 = (x+4)5

3x-12 = x+4

⇒x = 8 km/hr

7 0

3 years ago

Write 3 1/3 as an improper fraction.

Nataly_w [17]

10/3 is the answer
_______________

8 0

4 years ago

Read 2 more answers

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne

Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

$H_0: \bar x =12.7\\H_a: \bar x >12,7$

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = $\frac{6}{\sqrt{1000} } \\=0.1897$

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0

3 years ago