What is the pressure of 5.0 mol nitrogen gas in a 2.0 L container at 286 K
1 answer:
The "Ideal Gas Law Equations" is
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or <u>n</u>umber (in moles)
R= 8.3145
or 
T= Temperature (In Kelvin)
Plug into the equation and you're good!
If your teacher cares about sig figs,
2 sig figs (significant figures)
For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar<u />
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or <u>n</u>umber (in moles)
R= 8.3145
T= Temperature (In Kelvin)
Plug into the equation and you're good!
If your teacher cares about sig figs,
2 sig figs (significant figures)
For other units of pressure,
1 atm = 760 mmHG = 760 Torr = 101326 Pa = 1.01325 bar<u />
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Answer:
14,448 J of heat would it take to completely vaporize 172 g of this liquid at its boiling point.
Explanation:
The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to Q = m*L, where L is called the latent heat of the substance and depends on the type of phase change.
During the evaporation process, a substance goes from a liquid to a gaseous state and needs to absorb a certain amount of heat from its immediate surroundings, which results in its cooling. The heat absorbed is called the heat of vaporization.
So, it is called "heat of vaporization", the energy required to change 1 gram of substance from a liquid state to a gaseous state at the boiling point.
In this case, being:
- Q=?
- m= 172 g
- L= 84
and replacing in the expression Q = m*L you get:
Q=172 g*84
Q=14,448 J
<u><em>14,448 J of heat would it take to completely vaporize 172 g of this liquid at its boiling point.</em></u>