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xenn [34]
3 years ago
12

What is the volume of the air in a balloon that occupies 8.7 L at 50.0°C if the temperature is lowered to 25.0°C?

Chemistry
1 answer:
dangina [55]3 years ago
3 0

Answer:

8.03L

Explanation:

Given parameters:

Initial volume, V₁  = 8.7L

Initial temperature T₁  = 50°C , in Kelvin gives 50+273  = 323K

Final temperature T₂ = 25°C, in Kelvin gives 25 + 273  = 298K

Unknown:

Final volume V₂  = ?

Solution:

Since we are dealing with volume and temperature relationships under constant pressure, we simply apply the Charles's law.

Charles's law states that "the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant".

Mathematically, we have;

              \frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

where V andV T are volume and temperature, 1 and 2 are initial and final states.

Input the parameters and solve for V₂;

            \frac{8.7}{323}  =  \frac{V_{2} }{298}

          V₂  = 8.03L

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How many atoms in 5.01 mole of lead?
leva [86]

Answer:

30.17 × 10²³ atoms

Explanation:

Given data:

Number of moles of lead = 5.01 mol

Number of atoms = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

In given question:

1 mole = 6.022 × 10²³ atoms

5.01 mol × 6.022 × 10²³ atoms / 1 mol

30.17 × 10²³ atoms

3 0
3 years ago
How many atoms of oxygen are contained in 160 grams if N2O3?​
Juli2301 [7.4K]

Answer:

3.80x1024 grams containing if not that then above 80 grams 6 grams

Explanation:

3 0
2 years ago
Read 2 more answers
6. What does the symbol AH stand for?
Vesnalui [34]

the heat of reaction for a chemical reaction

4 0
3 years ago
A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
3 years ago
Hiw to separate and measure a mixture of iron fillings, sugar, and salt
Alecsey [184]
Add water to mixture to dissolve sugar then filter. sugared water will be the filtrate while the salt & iron fillings will be the residue. use magnet to attract iron fillings and remaining will be salt.
3 0
3 years ago
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