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3 years ago

10. What are the only types of passes allowed in floor hockey?

Physics

1 answer:

anygoal [31]3 years ago

3 0

The only type of passages allowed in floor hockey includes push passes and the wrist shot

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What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?

Zepler [3.9K]

Answer:

= 316.67 m/s^2

Explanation:

Acceleration formula =

A = $\frac{V_{f} - V_{i} }{t}$

$A = \frac{1000 - 50}{3}$

= $\frac{950}{3}$

= 316.67 m/s^2

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2 years ago

Can somebody please answer this correctly I will give brainliest

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2 years ago

An attack helicopter is equipped with a 20- mm cannon that fires 87 g shells in the forward direction with a muzzle speed of 853

uysha [10]

Answer

given,

mass of the shell = 87 g = 0.087 Kg

speed of the muzzle = 853 m/s

mass of the helicopter = 4410 kg

A burst of 176 shell fired in 2.93 s

resulting average force = ?

momentum of the shell = m v

= 0.087 x 853

= 74.21 kgm/s

momentum of 176 shell is = 176 p

= 176 x 74.21

= 13060.96

momentum of helicopter = - 13060.96 kgm/s

amount of speed reduce a = $\dfrac{13060.96}{M}$

a= $\dfrac{13060.96}{4410}$

a = 2.96 m/s²

velocity = \dfrac{2.96}{2.93}

v = 1.01 m/s

5 0

3 years ago

Read 2 more answers

A 12.5843-gram sample of metal bromide, MBr4, was dissolved and, after reaction with silver nitrate, AgNO3, all of the bromide w

barxatty [35]

Answer:

zirconium

Explanation:

Given, Mass of AgBr(s) = 23.0052 g

Molar mass of AgBr(s) = 187.77 g/mol

The formula for the calculation of moles is shown below:

$Moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles\ of\ AgBr= \frac{23.0052\ g}{187.77\ g/mol}$

$Moles\ of\ AgBr= 0.1225\ mol$

The reaction taking place is:

$MBr_4+4AgNO_3\rightarrow 4AgBr+M(NO_3)__4$

From the reaction,

4 moles of AgBr is produced when 1 mole of $MBr_4$ undergoes reaction

1 mole of AgBr is produced when 1 / 4 mole of $MBr_4$ undergoes reaction

0.1225 mole of AgBr is produced when $\frac {1}{4}\times 0.1225$ mole of $MBr_4$ undergoes reaction

Moles of $MBr_4$ got reacted = 0.030625 moles

Mass of the sample taken = 12.5843 g

Let the molar mass of the metal = x g/mol

So, Molar mass of $MBr_4$ = x + 4 × 79.904 g/mol = 319.616 + x g/mol

Thus,

$0.030625 = \frac{12.5843}{319.616 + x}$

Solve for x,

we get, x = 91.2999 g/mol

<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>

8 0

2 years ago

Please tell me why the answer is zero

Oduvanchick [21]

This question is checking to see whether you understand the meaning
of "displacement".

Displacement is a vector:

-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.

-- Its direction is the direction from the start-point to the end-point.

Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).

If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ?
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve. Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked !

So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point. But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point.
The Earth covered a huge distance in that year, but the displacement
is zero.

5 0

2 years ago

Read 2 more answers

10. What are the only types of passes allowed in floor hockey?​

10. What are the only types of passes allowed in floor hockey?