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Alexxx [7]
2 years ago
15

A student is running at her top speed of 5. 4m/s to catch a bus.

Physics
1 answer:
Kay [80]2 years ago
8 0

Answer:

A student is running at her top speed of 5. 4m/s to catch a bus.

Explanation:

Thats to fast

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Use the graph below to answer the following question: if average acceleration is calculated using the equation, “ change in velo
sergiy2304 [10]

Answer:

a=9\ cm/s^2

Explanation:

<u>Average Acceleration </u>

Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.

Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that. </em>

When t_2=4\ sec, the graph shows a value of v_2=36\ cm/s

When t_1=0\ sec, the object is at rest, v_1=0

We compute the average acceleration as

\displaystyle a=\frac{v_2-v_1}{t_2-t_1}

\displaystyle a=\frac{36\ cm/s-0\ cm/s}{4\ sec-0\ sec}

\displaystyle a=\frac{36\ cm/s}{4\ s}

\boxed{a=9\ cm/s^2}

6 0
3 years ago
La siguiente gráfica representa la velocidad como función del tiempo para dos carros que parten simultáneamente desde el mismo p
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Шада и я тебя понимаю с чего начать с того ни другого человека дал в долг у меня в здоровье
6 0
3 years ago
The main energy source during exercise of low to moderate intensity is
zhannawk [14.2K]

Answer:

THUS,THE MAJOR SOURCES OF ENERGY DURING EXERCISE ARE CARBOHYDRATES AND FATS.

Explanation:

6 0
3 years ago
What is the difference between speed and volocity?
Sliva [168]
The average speed is the distance per time ratio. velocity is the rate at which the position changes
3 0
2 years ago
6) 100 ml of water is initially at 20°C. 30,000 J of heat is added to the water. What is temperature change for the water?
vovangra [49]
<h2>Δt = 71.67 °C</h2>

The temperature change of water is equal to 71.67 °C

<h3>Explanation:</h3>

Given:

Amount of transferred energy = 30,000 K J

Mass of water = 100 ml

Initial temperature = 20°C

To find the change in temperature of water.

Formula for Heat capacity is given by

Q = m×c×Δt ........................................(1)

where:

Q = Heat capacity of the substance (in J)

m=mass of the substance being heated in grams(g)

c = the specific heat of the substance in J/(g.°C)

Δt = Change in temperature (in °C)

Δt = (Final temperature - Initial temperature) = T(f) - T(i)

Q = 30,000 J

Mass of water = m = 100 ml

1 ml = 1 g ................................................(2)

Therefore m = 100 ml = 100 g

Specific heat of water is c = 4.186 J /g.

Δt = ?

Substituting these in equation (1), we get

Q = m×c×Δt

Rearranging the terms for Δt,

Δt = \frac{Q}{m\times c}

Δt = \frac{30,000}{100\times 4.186}  = \frac{30,000}{418.6}= 71.67\°C

Δt = 71.67 °C

8 0
3 years ago
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