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Nimfa-mama [501]
2 years ago
8

What is refraction? this my in sta id-:akhilrawat9453​

Physics
2 answers:
My name is Ann [436]2 years ago
6 0

Explanation:

ij jdjcjxjjdjnndnxnsmxnjxjebxnc

White raven [17]2 years ago
4 0

Answer:

refers to the bending of light

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marta [7]
A. “I usually get 10 piece nugget meal with medium fries at McDonald’s with a McFlurry

B. I could replace the 10 piece nuggets with a grilled chicken wrap and replace the medium fries with a small fries then replace the mcflurry with either water or unsweetened tea.
3 0
3 years ago
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A bucket of water is being raised from a well using a rope. If the bucket of water has a mass of 6.2 kg, how much force (in N) m
Sholpan [36]

Answer:

6.2N force

Explanation:

According to Newton's second law of motion, force is equal to the product of the mass of a body and its acceleration. Mathematically,

Force = mass × acceleration

Given mass of bucket of water = 6.2kg

acceleration of the bucket = 1m/s²

Force exerted on the rope = 6.2 × 1

= 6.2N

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3 years ago
The amount of the lighted side of the moon you can see is the same during
attashe74 [19]

<u>Answer:</u>

The amount of the lighted side of the moon you can see is the same during "how much of the sunlit side of the moon faces Earth".

<u>Explanation:</u>

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The side of the Moon facing Earth is considered the near side, and the far side is called the reverse. The far side is often referred to as the "dark side" inaccurately but it is actually highlighted as often as the near side: once every 29.5 Earth days. During the New Moon the near side becomes blurred.

5 0
3 years ago
Please give me the answer of this question ​
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Da answer to your question is is is is is is is is is is is is

C
8 0
2 years ago
Water from Old Faithful Geyser shoots upward to a height of about 50 m once every 90 minutes. What must be the pressure in the h
Naya [18.7K]

Solution:

Given:

height of geyser, h = 50 m

speed of water at ground can be given by third eqn of motion with v = 0 m/s:

u^{2} = v^{2} + 2gh

putting v = 0 m/s in the above eqn, we get:

u = \sqrt{2gh}                      (1)

Now, pressure is given by:

\Delta p = \frac{1}{2}u^{2}\rho \\        (2)

where,

\Delta p = density of water = 1000 kg/m^{3}

g = 9.8 m/s^{2}

Using eqn (1) and (2):

\Delta p = \frac{1}{2}(\sqrt{2gh})^{2}\rho

⇒ \Delta p = \frac{1}{2}\rho gh

\Delta p = \frac{1}{2}\times2\times 1000\times 9.8\times 50 = \Delta p =   490000 Pa

p_{atm} = 101325 Pa

For absolute pressure, p:

p = \Delta p + p_{atm}

p = 490000 - 101325

p = 388675 Pa

Therefore, pressure in hot springs for the water to attain the height of 50m is 388675 Pa

5 0
3 years ago
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