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schepotkina [342]
3 years ago
15

What is the work required to stretch a spring with a spring constant k of 2500 N/m by 8 cm?

Physics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

the work required to stretch the spring is 8 J.

Explanation:

Given;

spring constant, k = 2500 N/m

extension of the spring, x = 8 cm = 0.08 m

The work required to stretch the spring is calculated as;

W =  \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 2500 \times 0.08^2\\\\W = 8 \ J

Therefore, the work required to stretch the spring is 8 J.

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