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4 years ago

Is one liter about an ounce a pint a quart or a gallon

Physics

2 answers:

Ymorist [56]4 years ago

5 0

Pints and ounces are both very small while gallons are very large so I would say about a Quart.

Mandarinka [93]4 years ago

4 0

Answer:

A quart

Explanation:

The conversion of different units in litres is defined below:

The value of 1 gallon is equal to 3.78541 litres.

The value of 1 pint is equal to 0.473176 litre.

The value of 1 ounce is equal to 0.0295735 litre.

The value of 1 quart is equal to 0.94635 litre.

Therefore, by seeing the above point the 1 quart is approximately equal to 1 litre.

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Terry usually rides his bike at 15 mph. If his riding speed is reduced by 3 mph, how far can he ride in 1.7 hours?

Serga [27]

Answer:

20.4 miles

Explanation:

Terry's normal speed while riding his bike = $15\ \text{mph}$

Speed is reduced by $3\ \text{mph}$ .

So his speed now is $15-3=12\ \text{mph}$

The time for which the distance needs to be found is $1.7\ \text{hours}$

Distance is given by

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance}=12\times 1.7=20.4\ \text{miles}$

So, the distance traveled in 1.7 hours is 20.4 miles.

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3 years ago

How many valence electrons does strontium (Sr) have? 1 2 5 6

Tresset [83]

Strontium has 2 valence electrons since it is in group 2

5 0

3 years ago

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A potter’s wheel moves from rest to an angular speed of 0.40 rev/s in 37.5 s.

svlad2 [7]

The angular acceleration of the potter's wheel is 0.067 rad/s².

The given parameters:

Final angular speed, ωf = 0.4 rev/s
Time of motion, t = 37.5 s

<h3>What is angular acceleration?</h3>

Angular acceleration of an object is the rate of change of angular speed of the object.

The angular acceleration of the potter's wheel is calculated as follows;

$\alpha = \frac{\Delta \omega }{t} \\\\\alpha = (0.4\ rev/s \times \frac{2 \pi \ rad}{1 \ rev} ) \times \frac{1}{37.5 \ s} \\\\\alpha = 0.067 \ rad/s^2$

Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².

Learn more about angular acceleration here: brainly.com/question/25129606

5 0

3 years ago

A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down th

pishuonlain [190]

The amount of work done during the kick is 200 Joules.

<h3>Formula for Work done </h3>

The formula for work done is Force× Distance

This is represented by fd

The force applied is 1,000 Newton

The displacement exerted by the force during kicking is 0.2meter

From this we can get the work done which is:

W= fd

= 1000N × 0.2m

= 200 Joules.

Read more about Work done here brainly.com/question/25191227

3 0

3 years ago

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Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

Step2247 [10]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

9 0

4 years ago

Read 2 more answers