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andreev551 [17]
4 years ago
11

Is one liter about an ounce a pint a quart or a gallon

Physics
2 answers:
Ymorist [56]4 years ago
5 0
Pints and ounces are both very small while gallons are very large so I would say about a Quart.
Mandarinka [93]4 years ago
4 0

Answer:

A quart

Explanation:

The conversion of different units in litres is defined below:

  • The value of 1 gallon is equal to 3.78541 litres.
  • The value of 1 pint is equal to 0.473176 litre.
  • The value of 1 ounce is equal to 0.0295735 litre.
  • The value of 1 quart is equal to 0.94635 litre.

Therefore, by seeing the above point the 1 quart is approximately equal to 1 litre.

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Lana71 [14]

Answer:

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Explanation:

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7 0
3 years ago
You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,
lbvjy [14]

Answer:

The value is T_c  =  12 .1 ^oC

Explanation:

From the question we are told that

The mass of the ice cube is m_i  =  7.50 *10^{-3} \  kg

The temperature of the ice cube is T_i = 0^o C

The mass of the copper cube is m_c  =  0.540 \  kg

The final temperature of both substance is T_f  =  0^oC

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

Q =  m_c  *  c_c *  [T_c  -  T_f ]

The specific heat of copper is c_c  = 385J/kg \cdot  ^oC

Generally the heat gained by the ice cube is mathematically represented as

Q_1 =  m_i * L

Here L is the latent heat of fusion of the ice with value L  =  3.34 * 10^{5} J/kg

So

Q_1 =  7.50 *10^{-3} * 3.34 * 10^{5}

=> Q_1 =  2505 \ J

So

2505  =  0.540  *  385 *  [T_c  - 0 ]

=>    T_c  =  12 .1 ^oC

4 0
3 years ago
How do I answer this question
maria [59]

Answer:

what question

Explanation:

6 0
4 years ago
Read 2 more answers
I need help someone help me
GaryK [48]

what do you need , i mean your help , let me see if i can help

5 0
3 years ago
For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel
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I think its half of pie so you divid that by 3.14 .
4 0
3 years ago
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