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2 years ago

Which demonstrates simple harmonic motion?

Physics

2 answers:

LUCKY_DIMON [66]2 years ago

7 0

Where are the pictures or options?

uysha [10]2 years ago

4 0

Answer:

A) a player dribbling a basketball

B) a chandelier swinging from the ceiling

C) a lion pacing the length of a cage

D) a spring compressed in a ballpoint pen

<u>(These are just the options)</u>

Explanation:

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The Pony Express was a mail delivery system in the Old West that used a series of men on horseback to deliver mail from St. Jose

aliya0001 [1]

Answer:

the given statement is False

Explanation:

given,

distance of the trail = 2000 miles long

each rider traveled = 100 miles

every fresh horse travel = 10 miles

to maintain speed of = 10 mile/hr

the given statement is

150 horses is used for each delivery.

if each horse is allowed to travel 10 miles to travel

distance traveled using 150 horses = 150 x 10

= 1500 miles

to travel 2000 miles horse required is equal to 200.

so, the given statement is False

4 0

3 years ago

You are working in a biology lab and learning to use a new ultracentrifuge for blood tests. The specifications for the centrifug

Sloan [31]

Answer:

Yes, correct

Explanation:

velocity, v = 470 m/s

radius, r = 0.15 m

The radial acceleration is the centripetal acceleration which always acts towards the centre of the circular centrifuge.

The formula for the centripetal acceleration is given by

$a =\frac{v^{2}}{r}$

$a =\frac{470^{2}}{0.15}$

a = 1472666.667

a = 150272.1 g

According to the question, we can get the acceleration as mentioned. So the claim is correct.

7 0

2 years ago

Read 2 more answers

As light shines from air to another medium, i = 42.0Â°. The light bends toward the normal and refracts at 38.0° What is

eduard

Answer:

1.09

Explanation:

8 0

3 years ago

Find the first three harmonics of a string of linear mass density 2. 00 g/m and length 0. 600 m when the tension in it is 50. 0

gavmur [86]

The first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

<h3>Velocity of the wave</h3>

The velocity of the wave is calculated as follows;

v = √T/μ

where;

T is tension
μ is mass per unit length = 2 g/m = 0.002 kg/m

v = √(50/0.002)

v = 158.1 m/s

<h3>First harmonic or fundamental frequency of the wave</h3>

f₀ = v/λ

where;

λ is the wavelength = 2L

f₀ = v/2L

f₀ = 158.1/(2 x 0.6)

f₀ = 131.8 Hz

<h3>Second harmonic of the wave</h3>

f₁ = 2f₀

f₁ = 2(131.8 Hz)

f₁ = 263.6 Hz

<h3>Third harmonic of the wave</h3>

f₂ = 3f₀

f₂ = 3(131.8 Hz)

f₂ = 395.4 Hz

Thus, the first three harmonics of the string are 131.8 Hz, 263.6 Hz and 395.4 Hz.

Learn more about harmonics here: brainly.com/question/4290297

#SPJ1

6 0

1 year ago

A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î

Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value $\vec{v}\times\vec{B}$

$(\vec{v}\times\vec{B})=3i+4j+11k$

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

$\vec{F}=q(\vec{v}\times\vec{B})$

Put the value into the formula

$\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)$

$\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}$

$|F|=2.6\times10^{-9}\ N$

Hence, The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

7 0

2 years ago