Protons and neutrons. Explanation:
Protons are massive, positively charged
nuclear particles.
I believe this question has the following sub questions:
1. When the climber ascends the mountain before
acclimating, ___ to restore homeostasis within the body. <span>
2. As the climber rehydrates and rests at a
basecamp, hemoglobin (Hb) is produced, which is the body's response to the
stress. As a result, ___ </span>
3. When the climber returns to sea level before
reacclimating, ___ to restore homeostasis within the body.
4. As the climber reacclimates to sea level,
hemoglobin is replaced at a lower rate, decreasing hemoglobin concentrations in
the blood. As a result, ___
The answers on each sub question are:
1) Equilibrium shifts to release O2<span>
<span>2) Equilibrium shifts to formation of HbO2</span>
<span>3) Equilibrium shifts to formation of HbO2</span>
<span>4) Equilibrium shifts to release O2</span></span>
Answer:
- 1 m/s, 20 m
Explanation:
u = 9 m/s, a = - 2 m/s^2, t = 5 sec
Let s be the displacement and v be the velocity after 5 seconds
Use first equation of motion.
v = u + a t
v = 9 - 2 x 5 = 9 - 10 = - 1 m/s
Use second equation of motion
s = u t + 1/2 a t^2
s = 9 x 5 - 1/2 x 2 x 5 x 5
s = 45 - 25 = 20 m
Answer:
t = 1.27 x 10⁹ s
Explanation:
First, we will find the volume of the wire:
Volume = V = AL
where,
A = Cross-sectional area of wire = πr² = π(1 cm)² = π(0.01 m)² = 3.14 x 10⁻⁴ m²
L = Length of wire = 150 km = 150000 m
Therefore,
V = 47.12 m³
Now, we will find the number of electrons in the wire:
No. of electrons = n = (Electrons per unit Volume)(V)
n = (8.43 x 10²⁸ electrons/m³)(47.12 m³)
n = 3.97 x 10³⁰ electrons
Now, we will use the formula of current to find out the time taken by each electron to cross the wire:
where,
t = time = ?
I = current = 500 A
q = total charge = (n)(chareg on one electron)
q = (3.97 x 10³⁰ electrons)(1.6 x 10⁻¹⁹ C/electron)
q = 6.36 x 10¹¹ C
Therefore,
<u>t = 1.27 x 10⁹ s</u>
