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3 years ago

Test yourself: 1

Physics

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

F = 1500 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of all forces must be equal to the product of mass by acceleration.

ΣF = m*a

F = 1000*1.5

F = 1500 [N]

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Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will

evablogger [386]

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

$0-(u)^2=2\times a\times s$

$s_a=\frac{u^2}{2a}------1$

For car B

$0-(2u)^2=2\times a\times s_b$

$s_b=\frac{4u^2}{2a}----2$

divide 1 and 2 we get

$\frac{s_a}{s_b}=\frac{1}{4}$

thus $s_b=4\cdot s_a$

distance traveled by car B is four time of car A

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2 years ago

Three small children of mas 20.0 kg, 24.0 kg, and 16.0 kg, respectively, hold hands, as

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Answer:

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3 years ago

An automobile starter motor has an equivalent resistance of 0.0500Ω and is supplied by a 12.0-V battery with a 0.0100-Ω internal

alexandr1967 [171]

Answer

given,

resistance = 0.05 Ω

internal resistance of battery = 0.01 Ω

electromotive force = 12 V

a) ohm's law

V = IR

and volage

$V = \epsilon - Ir$

now,

$IR = \epsilon - Ir$

$I(R+r) = \epsilon$

$I= \dfrac{\epsilon}{R+r}$

inserting the values

$I= \dfrac{12}{0.05+0.01}$

I = 200 A

b) Voltage

V = I R

V = 200 x 0.05

V = 10 V

c) Power

P = I V

P = 200 x 10 = 2000 W

d) total resistance = 0.05 + 0.09 = 0.14 Ω

$I= \dfrac{\epsilon}{R+r}$

$I= \dfrac{12}{0.14+0.01}$

I = 80 A

V = 80 x 0.05 = 4 V

P = 4 x 80 = 320 W

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2 years ago

Read 2 more answers

A book is at rest on a table. Identify the correct free-body diagram for this situation.

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Show a picture .. of what your doing

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2 years ago

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Objects 1 and 2

sattari [20]

Answer:

12 units

Explanation:

Original F = C q1q2/r^2 now change the parameters

New F = C 1/3 q1 2 q2 / (2r)^2

= 2/12 C q1q2/r^2 <=======the new force is 1/6 of original

1/6 * 72 = 12 units

3 0

1 year ago