I dont think it can be solved as time is not mentioned
We have that the see-saw will be balance if a weight of
is added to Nural's side of the see-saw

From the Question we are told that
Wan’s mass is 
Nurul’s mass is 
Generally
The Will be balance when the weight on both sides of the see-saw are equal




In conclusion
The see-saw will be balance if a weight of
is added to Nural's side of the see-saw

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It is A or D but I believe A
X2 = 60
/ 2 / 2
x = 30
Plus or minus square root 60
Answer:
true
Explanation:
Area = πr²
Differentiating in respect to r
we get,
dA/dr = 2πr
using chain rule,

since r = 4feet
so ,
2π(4) = 8π