Answer:
23
Explanation:
First, we need to convert the hose diameter from inches to meters.
0.75 in × (2.54 cm / in) × (1 m / 100 cm) = 0.0191 m
Calculate the flow rate given the velocity and hose diameter:
Q = vA
Q = v (¼ π d²)
Q = (0.30 m/s) (¼ π (0.0191 m)²)
Q = 8.55×10⁻⁵ m³/s
Find the volume of the pool:
V = π r² h
V = π (1.5 m)² (1.0 m)
V = 7.07 m³
Find the time:
t = V / Q
t = (7.07 m³) / (8.55×10⁻⁵ m³/s)
t = 82700 s
t = 23 hr
Answer:
M a = (M1 + M2) a = F Newton's Second Law
F = (M2 - M1) g net force on the system
a = (M2 - M1) / (M1 + M2) g
a = (9 - 7) / (9 + 7) g = 2 / 16 * 10.0 m/s^2 = 1.25 m/s^2
Answer:
10.44 liters of gasoline.
Explanation:
First, we need to convert the units of the car from mi/gal to km/L as follows:
![mileage = 32.0 \frac{mi}{gal}*\frac{1.609 km}{1 mi}*\frac{1 gal}{3.785 L} = 13.60 km/L](https://tex.z-dn.net/?f=%20mileage%20%3D%2032.0%20%5Cfrac%7Bmi%7D%7Bgal%7D%2A%5Cfrac%7B1.609%20km%7D%7B1%20mi%7D%2A%5Cfrac%7B1%20gal%7D%7B3.785%20L%7D%20%3D%2013.60%20km%2FL%20)
That means that for every liter of gasoline the car travels 13.60 kilometers.
So, to complete a 142-km trip in Europe the volume of gasoline needed is:
![V = \frac{1 L}{13.60 km}*142 km = 10.44 L](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%7B1%20L%7D%7B13.60%20km%7D%2A142%20km%20%3D%2010.44%20L%20)
Therefore, to complete a 142-km trip in Europe we need to buy 10.44 liters of gasoline.
I hope it helps you!
Answer:
I will specify a value of 0.009T for the alternator’s magnetic field
Explanation:
E_peak = 14 V
d = 10cm = 0.1m, so r = 0.1/2 =0.05m
N = 250 turns
f = 1200rpm = (1200rp/m x 1m/60sec) = 20 revolutions per second
At peak performance, peak voltage is given by the equation;
E_peak = NABω
Let's make the magnetic field B the subject;
B = E_peak/(NAω)
Now we know that ω = 2πf
Thus, ω = 2π x 20 revs/s = 125.664 revs/s.
Let's convert it to the standard unit which is rad/s.
1 rev/s = 6.283 rad/s
Thus, 125.664 revs/s = 125.664 x 6.283 = 789.55 rad/s
Area (A) = πr² = π x 0.05² = 0.007854 m²
Thus, plugging in the relevant values to get;
B = 14/[(250 x 0.007854 x 789.55)] = 0.009T
Answer:
Power rating on the blender = 3809.52 Watts
Explanation:
We have expression for power equal to ratio of work and time,
Energy used by blender = Work done by electricity = 0.8 MJ = ![0.8*10^6J=800000J](https://tex.z-dn.net/?f=0.8%2A10%5E6J%3D800000J)
Time of using blender = 3.5 minutes = 210 seconds
So power of blender = 800000/210 = 3809.52 Watts
Power rating on the blender = 3809.52 Watts