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Thepotemich [5.8K]
3 years ago
9

A compact fluorescent bulb is 17.0% efficient. How much energy input would be required for the bulb to produce 252 J of light en

ergy?
What time of energy is the waste output and how much would be created?

Help
Physics
1 answer:
Arisa [49]3 years ago
3 0

Answer:

1482.35J

Explanation:

Efficency=(output energy/input energy) x100

17.0 =(252/input energy) x100

input energy =100x252/17=1482.35J

wasted energy=1482.35-252=1230.35J

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To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

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Here,

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The linear charge density can be written as,

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Replacing,

E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}

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The initial and final electric Force can be written as function of the charge and the electric field as

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F_f = E_f q

If we replace the value for the electric field we have,

F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})

Length is one third at the end, then

F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})

The ratio of the force is

\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}

\frac{F_f}{F_i} = 3

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A student eats a candy bar that contains 1.57 x 106 J of energy. If the student has a mass of 81.8 kg, how high will he have to
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Answer:abb

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The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The t
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Answer:

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Explanation:

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If a solution is forced to dissolve more solute than it normally can dissolve, the solution is
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