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Valentin [98]
3 years ago
5

The technique of using guidelines and reference points

Engineering
1 answer:
inysia [295]3 years ago
3 0

Answer:

Linear perspective.

Explanation:

The technique of using guidelines and reference points to create a realistic sense (illusion) of depth in a two-dimensional artwork is called linear perspective.

In linear perspective, the realistic sense (illusion) of depth is typically created or done on a flat surface so that all the orthogonal or parallel lines can converge at a single vanish point of the drawing's horizon line. Thus, this technique make drawings or paintings of objects to look real.

Hence, linear perspective comprises of three (3) basic components and these are;

1. Vanishing point.

2. Horizon line.

3. Orthogonal or parallel lines.

Generally, drawings (objects) that are drawn or created using linear perspective appear to be larger when viewed closely while drawings (objects) that are further away, appear to be small.

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Information or signals entered into a computer system is
Virty [35]

<em>Logs.</em>

<em>Like data logs. Sometimes people make these logs to keep tabs on other people or to get important information put down somewhere that way it is saved and can be looked back upon later. Anytime someone makes an action on the computer, it makes a TMP file representing a log of what you want it to do before the computer quickly get's rid of the file.</em>

<em>-Ɽ3₮Ɽ0 Ⱬ3Ɽ0</em>

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8 0
3 years ago
What motivated software engineers to move from the waterfall model to the incremental or spiral model
scoray [572]

Answer:

1. They needed to develop multiple components in software programs.

2. The ability to overlap the development to be more evolutionary in nature.

3. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.

Explanation:

Software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

In SDLC, a waterfall model can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.

An incremental model refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.

Also, a spiral model can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.

<em>What motivated software engineers to move from the waterfall model to the incremental or spiral model is actually due to the following fact;</em>

  • They needed to develop multiple components in software programs.
  • The ability to overlap the development to be more evolutionary in nature.
  • The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.
6 0
3 years ago
Witch truck company is better.<br><br> Ram <br> Ford <br> Toyoda<br> GMC
arlik [135]
Ram is the better truck company
7 0
3 years ago
Read 2 more answers
Systematic searching is a skill that takes ________ to master.
bagirrra123 [75]

Answer: B, repetitive practice! hope this helps. :)

Explanation:

7 0
4 years ago
Read 2 more answers
Water vapor at 100 psi, 500 F and a velocity of 100 ft./sec enters a nozzle operating at steady sate and expands adiabatically t
almond37 [142]

Answer:

a)exit velocity of the steam, V2 = 2016.8 ft/s

b) the amount of entropy produced is 0.006 Btu/Ibm.R

Explanation:

Given:

P1 = 100 psi

V1 = 100 ft./sec

T1 = 500f

P2 = 40 psi

n = 95% = 0.95

a) for nozzle:

Let's apply steady gas equation.

h_1 + \frac{(v_1) ^2}{2} = h_2 + \frac{(v_2)^2}{2}

h1 and h2 = inlet and exit enthalpy respectively.

At T1 = 500f and P1 = 100 psi,

h1 = 1278.8 Btu/Ibm

s1 = 1.708 Btu/Ibm.R

At P2 = 40psi and s1 = 1.708 Btu/Ibm.R

1193.5 Btu/Ibm

Let's find the actual h2 using the formula :

n = \frac{h_1 - h_2*}{h_1 - h_2}

n = \frac{1278.8 - h_2*}{1278.8 - 1193.5}

solving for h2, we have

h_2 = 1197.77 Btu/Ibm

Take Btu/Ibm = 25037 ft²/s²

Using the first equation, exit velocity of the steam =

(1278.8 * 25037) + \frac{(100)^2}{2}= (1197.77*25037)+ \frac{(V_2)^2}{2}

Solving for V2, we have

V2 = 2016.8 ft/s

b) The amount of entropy produced in BTU/ lbm R will be calculated using :

Δs = s2 - s1

Where s1 = 1.708 Btu/Ibm.R

At h2 = 1197.77 Btu/Ibm and P2 =40 psi,

S2 = 1.714 Btu/Ibm.R

Therefore, amount of entropy produced will be:

Δs = 1.714Btu/Ibm.R - 1.708Btu/Ibm.R

= 0.006 Btu/Ibm.R

3 0
3 years ago
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