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Lera25 [3.4K]
2 years ago
5

A weather balloon has a volume of 105L at 0.97 atm when the temperature is 318K. What is the volume

Chemistry
1 answer:
chubhunter [2.5K]2 years ago
3 0

Answer:

89 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 0.97 atm
  • Initial volume (V₁): 105 L
  • Initial temperature (T₁): 318 K
  • Final pressure (P₂): 1.05 atm
  • Final volume (V₂): ?
  • Final temperature (T₂): 293 K

Step 2: Calculate the final volume of the weather balloon

If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L

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Answer:

Of the following substances, <u>PCl₃</u> has the highest boiling point

Explanation:

The given substances and their boiling point from online resources are;

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2C4 H10 + 13O2 -→ 8CO2 + 10H2O If 356 moles of O2 are available to react, how many moles of CO2 will fom?
nlexa [21]

Answer:

Answer:

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Explanation:

The mole ratio is the relative proportion of the moles of products or reactants that participate in the reaction according to the chemical equation.

The chemical equation given is:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Once you check that the equation is balanced, you can set the mole ratios for all the reactants and products. The coefficients used in front of each reactant and product, in the balanced chemical equation, tells the mole ratios.

In this case, they are: 2 mol C₄H₁₀ :  13 mol O₂ : 8 mol CO₂ : 10 mol H₂O

Since you are asked about the mole ratio of C₄H₁₀ and CO₂ it is:

2 mol C₄H₁₀ : 8 mol CO₂ , which dividing by 2, simplifies to

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evablogger [386]

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Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

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The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

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Answer:

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