Answer:
Option 3. The catalyst does not affect the enthalpy change (
) of a reaction.
Explanation:
As its name suggests, the enthalpy change of a reaction () is the difference between the enthalpy of the products and the reactants.
On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.
In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change of the reaction would stay the same.
Refer to an energy profile diagram. Enthalpy change of the reaction measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.
Answer:
Baking soda has a ph of 9
Explanation:
Given:
128g sample of titanium
2808J of heat energy
specific heat of titanium is 0.523 J/ g °C.
Required:
Change in temperature
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
Plugging in the
values into the equation
H = mCpT
2808J = (128g) (0.523
J /g °C) T
T
= 41.9 °C
If the patient has to take 2 tablets every 8 hours for 7 days.
24/8=3 3*2=6
this means that he patient will have to take 6 tablets every day.
6*7=42 And the patient must take 42 tablets in all 7 days
Hope this helps! :)
Thin layer chromatography(TLC) works with the principle of separation through adsorption.
It is used in the isolation and extraction of lipids through the following steps:
- apply the lipid samples spots in the bottom of the plate.
- also apply sample solution to the marked spot
- pour the mobile phase into the TLC chamber and use a moist filter paper to cover it. this is done to maintain equal humidity.
- then place the plate in the TLC chamber and close it with a lid.
- the plate is immersed into the solvent (mobile phase) for its development. this is done, keeping in mind that the sample spot should be above the solvent.
- once the sample spots are developed, they are removed and dried.
- this is later viewed using the UV light chamber to see the isolation of the lipid sample.
Learn more here:
brainly.com/question/3137660
