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nevsk [136]
3 years ago
9

17. What is the symbol for the element that forms a.

Chemistry
1 answer:
stepladder [879]3 years ago
8 0
The answer is (C) Al
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Transuranium elements are elements larger than uranium that are produced via transmutation.
steposvetlana [31]
True.  Atoms with atomic numbers higher than 92 are not very stable and have half lives shorter than the age of the earth so they are not found naturally.  Due to that, the process of transmutation must be used to get atoms with the atomic number higher than 92.
4 0
3 years ago
Write the IUPAC name OF THE FOLLOWING COMPOUNDS
goldenfox [79]

Answer:

Explanation:

a) 2 chloro butane

b) 2-3 dimethyl butane

c) 2 bromo 3 nitro pentane

d) 2-3 trimethyl pentane

e) 2-bromo,3-methyl,4-nitro hexane

f) 2-methyl cyclo butane

7 0
4 years ago
At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?
Nadya [2.5K]

Answer:

V = 57.39 L

Explanation:

Given that,

Temperature, T = 300 K

Pressure, P = 0.987 atm

No. of moles of Ne, n = 2.30 mol

We need to find the volume of Ne. We know that, the ideal gas law is as follows :

PV = nRT

Where

P is pressure and R is gas constant

V=\dfrac{nRT}{P}\\\\V=\dfrac{2.3\times 0.0821\times 300}{0.987 }\\\\V=57.39\ L

So, the volume of the Ne is 57.39 L.

3 0
3 years ago
Of the atoms below, __________ is the most electronegative.<br> PLZ HELP I'LL AWARD BRINLIEST.
Readme [11.4K]

Hello sir, The answer that you are looking for is fluorine. Fluorine is the most electronegative atom. I am also sorry for calling you sir. I didn't know you were a woman.

8 0
4 years ago
12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate
Lilit [14]

For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K  is mathematically given as

Ecell = 0.577 V

<h3 /><h3>What is the cell potential at 298 K?</h3>

Generally, the equation for the Oxidation and Reduction  is mathematically given as

Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O

Sn+2(aq) + 2e- ------------ Sn(s) ] x 3  ...R

Reaction

 2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)

Therefore

Eicell = - 0.14 - ( - 0.74)

Eicell = 0.60

In conclusion

Ecell= E0cell - \frac{0.0591}{n} * \frac{log[Cr+3]^2}{ [ Sn+2]^3}

Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}

Ecell = 0.577 V

Read more about Temperature

brainly.com/question/13439286

5 0
3 years ago
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