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Katarina [22]
2 years ago
5

Living organisms need energy to carry on their life processes. Photosynthesis is a process that allows for photosynthesizing org

anisms, such as algae and green plants, to produce their own materials for energy production and survival. This process can be outlined as a simplified chemical equation containing reactants (goes into the process) and products (made/comes out of the process).Using your knowledge of science and figures above, select the choice that accurately expresses photosynthesis.

Chemistry
1 answer:
Ad libitum [116K]2 years ago
3 0

the correct combo is C

We know sunlight is key factor in photosynthesis so A and D are out.

we also know plants get their bulk by breaking up co2 and using the carbon which releases oxygen as a byproduct so B is also out of the question.

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Answer:

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In which of the following is the symbol for the ion and the number of electrons it contains given correctly?
tensa zangetsu [6.8K]
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3 years ago
A sample of sodium reacts completely with 0.497 kg of chlorine, forming 819 g of sodium chloride. what mass of sodium reacted?
Slav-nsk [51]

Sodium reacts to chlorine and gives NaCl. The balanced reaction is given below:

2Na + Cl₂→ 2NaCl. Two moles Na reacts with one mole Cl₂ and produces two moles of NaCl. Atomic mass of Na= 23, Molar mass of Cl₂= 71, molar mass of NaCl=58.5.

So, 46 g Na reacts with 71 g of Cl₂ and produces (2 X 58.5)g = 117 g of NaCl. As per question Na reacts completely which means Na is the limiting reagent. So, number of moles of Na reacts = number moles of NaCl produced.

NaCl produced= 819 g= (819/58.5) moles= 15.69 moles. Therefore, 15.69 moles = 15.69 X 23 g=360.87 g of Na reacted.

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3 years ago
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3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

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Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

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The mean free path is related to the collision cross section by the following equation:

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Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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