Answer is: the maximum wavelength of light is 7.34 × 10⁻⁷ m.
E= 163 kJ/mol; bond energy of one mole of nitrogen.
E = 163000 J/mol ÷ 6.022·10²³ 1/mol.
E = 2.707·10⁻¹⁹ J; bond energy per molecule.
E = h·c/λ.
c = 3.00 × 10⁸ m/s; light speed.
h = 6.62607004·10⁻³⁴ J·s; Planck constant.
λ(photon) = h·c/E.
λ(photon) = 6.62607004·10⁻³⁴ J·s · 3.00 × 10⁸ m/s ÷ 2.707·10⁻¹⁹ J.
λ(photon) = 7.34 × 10⁻⁷ m.
λ(photon) = 734 nm.
Any type of magnet can attract iron or iron materials
Based on the ideal gas relation:
PV = nRT
where P = pressure ; V = volume ; T = temperature
n = number of moles; R = gas constant = 0.0821 L atm/mol-K
Step 1: Find the number of moles of O2
n = PV/RT = 1 * 3.90/0.0821*273 = 0.1740 moles
Step 2: Calculate the molecules of O2
Now, 1 mole of O2 corresponds to 6.023 * 10²³ molecules of O2
Therefore, 0.1740 moles of O2 corresponds to-
0.1740 moles of O2 * 6.023*10²³ molecules of O2/1 mole of O2
= 1.048 * 10²³ molecules of O2
The signs of ΔS° and ΔH° will be negative.
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Combustion reactions must involve O2 as one reactant.
Consider the combustion of butane gas:
C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g)
4 + 13/2 4 + 5
10.5 mol -------------> 9 mol
As the number of moles decreases entropy will decrease
so ΔS° = negative
since this example for combustion reaction heat is released (exothermic)
so ΔH° = negative.
Learn more about ΔS° here:
brainly.com/question/3784176
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Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that and , then the eccentricity of the ellipse is:
The eccentricity of the ellipse is 0.252.