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____ [38]
2 years ago
14

A typical carbon atom has six protons, six neutrons, and six electrons. Which of these has the least amount of mass?

Physics
1 answer:
Butoxors [25]2 years ago
6 0

One proton or one neutron have very close to the same mass.

Their mass is about the same as the mass of 1,840 electrons !
So six electrons have roughly the same mass as 0.0033 of one
proton or one neutron.

Yes, these masses are very tiny.  None of them was ever measured
until the 20th Century.  But all of them have now been measured,
very precisely and accurately.  This is very impressive, and should
give us a lot of admiration for scientists of the past hundred years.
It would be very interesting to look around online and find out
how they did it.

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On a balanced seesaw, a boy three times as heavy as his partner sits
slega [8]

Answer:

1/3 the distance from the fulcrum

Explanation:

On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

W_1 d_1 = W_2 d_2

where

W1 is the weight of the boy

d1 is its distance from the fulcrum

W2 is the weight of his partner

d2 is the distance of the partner from the fulcrum

In this problem, we know that the boy is three times as heavy as his partner, so

W_1 = 3 W_2

If we substitute this into the equation, we find:

(3 W_2) d_1 = W_2 d_2

and by simplifying:

3 d_1 = d_2\\d_1 = \frac{1}{3}d_2

which means that the boy sits at 1/3 the distance from the fulcrum.

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3 years ago
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At what point on the hill will the car have zero gravitational potential energy?
Mila [183]
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it is determined that a certain light wave has a wavelength of 3.012x10^-12 m. the light travels at 2.99x10^8 m/s. what is the f
Dahasolnce [82]

Answer:

9.93\times 10^{19}Hz

Explanation:

Speed of light is the product of its wavelength and frequency, expressed as

S=fw

Where s represent speed, f is frequency while w is wavelength

Making f the subject of the formula then

f=s/w

Substituting 2.99x10^8 m/s for s and 3.012x10^-12 m for w then

f=\frac {2.99\times 10^{8}}{3.012\times 10^{-12}}=9.926958831341\times 10^{19}\\f\approx 9.93\times 10^{19}Hz

Therefore, the frequency equals to 9.93\times 10^{19}Hz

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