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3 years ago

A typical carbon atom has six protons, six neutrons, and six electrons. Which of these has the least amount of mass?

1 answer:

6 0

One proton or one neutron have very close to the same mass.

Their mass is about the same as the mass of 1,840 electrons !
So six electrons have roughly the same mass as 0.0033 of one
proton or one neutron.

Yes, these masses are very tiny. None of them was ever measured
until the 20th Century. But all of them have now been measured,
very precisely and accurately. This is very impressive, and should
give us a lot of admiration for scientists of the past hundred years.
It would be very interesting to look around online and find out
how they did it.

You might be interested in

Describe the four factors that affect resistance.

defon

There are four factors affecting resistance which are Temperature, Length of wire, Area of the cross-section of wire and nature of the material. When there is current in a conductive material, the free electrons move through the material and occasionally collide with atoms.

8 0

3 years ago

Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr

nordsb [41]

Answer:

$W=3456 N$

Explanation:

Force 1 $F_1=3456$

Force 2 $F_2=2333N$

Acceleration at stage 2 $a_2=0.39$

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

$W=3456 N$

5 0

3 years ago

A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c

Jlenok [28]

Answer:

8962.5 N

Explanation:

From fundamental kinematics equations, acceleration, a is given by $a=\frac {v-u}{t}$ where v is final velocity, u is initial velocity and t is time

We also know that force is a product of mass and acceleration of an object and substituting $a=\frac {v-u}{t}$ in the formula F=ma we obtain

$F=ma=m\frac {v-u}{t}$ where m is the mass of the body

$F=60\times\frac {0-23.9}{0.16}=-8962.5 N$

Therefore, the force is 8962.5 N

4 0

4 years ago

A current 1A in the human body is extremely dangerous.

zmey [24]

a) Potential difference needed: 10,000 V

b) Because the potential difference in the house is maximum 230 V

Explanation:

The relationship between current, potential difference and resistance in a conductor is given by Ohm's law:

$V=RI$

where

V is the potential difference

R is the resistance

I is the current

The resistance of the human body is estimated to be as high as $100,000 \Omega$ for a dry body and as low as $1000 \Omega$ for a wet body: in this problem, we use a value in the middle,

$R=10,000 \Omega$

Therefore, the potential difference needed to produce a current of

$I=1 A$

$V=(10,000)(1)=10,000 V$

Here we want to estimate if it is likely or not to get injured by an electric current in a house.

The amount of current that can be fatal is $I=1 A$ . From part a), we saw that in order to produce this current through the human body, a potential difference of

$V=10,000 V$

is needed.

However, the electricity that reaches the houses and then is connected to the household appliances has a potential difference of

V = 230 V

This value is much lower than 10,000 V, therefore the electricity in the house is unlikely to cause injures to human body.

Learn more about potential difference:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

6 0

3 years ago

A 2000 kg car moving at 100 km/h crosses the top of a hill with a radius of curvature of 100 m. What is the normal force exerted

Tpy6a [65]

Answer:

The normal force the seat exerted on the driver is 125 N.

Explanation:

Given;

mass of the car, m = 2000 kg

speed of the car, u = 100 km/h = 27.78 m/s

radius of curvature of the hill, r = 100 m

mass of the driver, = 60 kg

The centripetal force of the driver at top of the hill is given as;

$F_c = F_g - F_N$

where;

Fc is the centripetal force

$F_g$ is downward force due to weight of the driver

$F_N$ is upward or normal force on the drive

$F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N$

Therefore, the normal force the seat exerted on the driver is 125 N.

6 0

3 years ago