Answer:
The formula of acceleration is final velocity-initial velocity÷time taken
Explanation:
v-u/t
Answer:
![K_{goal}=1.793*10^{-33}](https://tex.z-dn.net/?f=K_%7Bgoal%7D%3D1.793%2A10%5E%7B-33%7D)
Explanation:
N2(g)+O2(g)⇌2NO(g), ![K_1 = 4.10*10^{-31}](https://tex.z-dn.net/?f=K_1%20%3D%204.10%2A10%5E%7B-31%7D)
N2(g)+2H2(g)⇌N2H4(g), ![K_2 = 7.40*10^{-26}](https://tex.z-dn.net/?f=K_2%20%3D%207.40%2A10%5E%7B-26%7D)
2H2O(g)⇌2H2(g)+O2(g), ![K_3 = 1.06*10^{-10}](https://tex.z-dn.net/?f=K_3%20%3D%201.06%2A10%5E%7B-10%7D)
If we add above reaction we will get:
2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)
Equilibrium constant for Eq (1) is ![K_1*K_3*K_3](https://tex.z-dn.net/?f=K_1%2AK_3%2AK_3)
Divide Eq (1) by 2, it will become:
N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)
Equilibrium constant for Eq (2) is ![(K_1*K_3*K_3)^{1/2}](https://tex.z-dn.net/?f=%28K_1%2AK_3%2AK_3%29%5E%7B1%2F2%7D)
![Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}](https://tex.z-dn.net/?f=Equilibrium%20constant%20%3DK_%7Bgoal%7D%3D%20%28K_1%2AK_2%2AK_3%29%5E%7B1%2F2%7D%5C%5CK_%7Bgoal%7D%3D%20%284.10%2A10%5E%7B-31%7D%20%2A7.40%2A10%5E%7B-26%7D%2A1.06%2A10%5E%7B-10%7D%29%5E%7B1%2F2%7D%5C%5CK_%7Bgoal%7D%3D1.793%2A10%5E%7B-33%7D)
Explanation:
A physical change is one that alters the physical properties of matter (particularly the form and state).
A chemical change is one in which new kind of matter is formed. It is always accompanied by energy changes (evolution or absorption of energy in form of heat or light or both).
Now, the salient differences between physical and chemical changes;
- Physical changes are easily reversible whereas chemical changes are not easily reversible.
- Physical changes lead to the production of no new kinds of matter whereas chemical changes leads to the production of new kinds of matter.
- Physical changes involves no change in mass whereas chemical changes involves change in mass.
- Physical changes require little energy whereas considerable amount of energy is needed for chemical changes.
The power used by Alex to drag the log across the yard is determined as 2,656 W.
<h3>Mass of the log</h3>
The mass of the log is calculated as follows;
W = mg
m = W/g
m = (400)/9.8
m = 40.82 kg
<h3>Velocity of the log</h3>
K.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 900)/(40.82)
v² = 44.096
v = 6.64 m/s
<h3>Power used by Alex</h3>
P = Fv
P = 400 x 6.64
P = 2,656 W
Learn more about power here: brainly.com/question/13881533
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Answer:
(iodine?) heptabromide
Explanation:
Not sure what element Ig is but use that name and then heptabromide.