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bazaltina [42]
3 years ago
8

Compare the properties of protons neutrons and electrons

Chemistry
2 answers:
butalik [34]3 years ago
6 0
Protons are positively charged. Neutrons have no charge. Electrons have a negative charge. Protons and neutrons are in the nucleus. Electrons revolve around the nucleus. 
meriva3 years ago
3 0
Electrons are negatively-charged particles and are found outside the nucleus of the atom, They interact with other electrons of other atoms that result to different properties of atoms. They also determine the charge of the atom, or more preferably, the ion. For a neutral atom, they have the same number as that of the protons. Protons are positively-charged particles and are found inside the nucleus along with the neutrons. Protons and neutrons are collectively called nucleons. Protons determine the atomic number of the atom. Neutrons, on the other hand, are neutrally-charged particles and are found inside the nucleus. Along with the proton, they constitute the mass of the whole atom. Atoms of the same element but with a different number of neutrons are called isotopes.


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3 years ago
Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce
levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca^{2+}(aq) and 0.0390 M Ag^{+}(aq). What will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate? What percentage of the Ca^{2+}(aq) can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

      Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}

[Ag^{+}] = 0.0390 M

When Ag_{2}SO_{4} precipitates then expression for K_{sp} will be as follows.

         K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]

        1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]

       [SO^{2-}_{4}] = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

         CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}

      K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788

           [Ca^{2+}] = 0.00625 M

Now, we will calculate the percentage of Ca^{2+} remaining in the solution as follows.

               \frac{0.00625}{0.05} \times 100

                 = 12.5%

And, the percentage of Ca^{2+} that can be separated is as follows.

                     100 - 12.5

                     = 87.5%

Thus, we can conclude that 87.5% will be the concentration of Ca^{2+}(aq) when Ag_{2}SO_{4}(s) begins to precipitate.

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2 years ago
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vesna_86 [32]

Answer:

The material that would most likely slow the flow of electricity is plastic.

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