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icang [17]
3 years ago
5

Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffre

y is experiencing psychomotor________
Physics
1 answer:
lana [24]3 years ago
7 0

Answer:

R.E.T.A.R.D.A.T.I.O.N

Explanation:

It won't let me spell it normal

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Does sound travels through your skull to your ear when you speak ? If yes then how ?
Maksim231197 [3]
Sound travels through waves, more specifically, through vibrations. They do not go from skull to ear, but they can go from ear to brain, or skull to brain. Ear to brain is simply vibrations traveling from outer ear, to inner ear, to the brain. Skull to brain, otherwise known as "bone conduction", has the vibrations hitting the skull, then to the temproal bone, then to the inner ear where the brain picks it up.
5 0
3 years ago
Two cars travel westward along a straight highway, one at a constant velocity of 85 km/h, and the other at a constant velocity o
spayn [35]

To solve letter a:

d1 = 85t1 = 16 km, 
85t1 = 16, 
t1 = 16 / 85 = 0.1882 h = 11.29 min. 

d2 = 115t2 = 16 km, 
115t2 = 16, 
t2 = 16 / 115 = 0.139 h = 8.35 min. 

t1 - t2 = 11.29 - 8.35 = 2.94 min. 
Car #2 arrives 2.94 minutes sooner.

To solve letter b:

15 min = 1/4 h = 0.25 h. 
d1 = d2, 
115t = 85(t + 0.25), 
115t = 85t + 21.25, 
115t - 85t = 21.25, 
30t = 21.25, 
t = 21.25 / 30 = 0.71 h, 

d = 115 * 0.71 = 81.65 km.

8 0
3 years ago
Why couldnt mendeleev organize the entire table during his research
NARA [144]
Cause he left out the noble gases out of the periodic table for one good reason, 1: He did not know them
6 0
3 years ago
Read 2 more answers
A train 471 m long is moving on a straight track with a speed of 75.1 km/h. The engineer applies the brakes at a crossing, and l
hram777 [196]

Answer:

t = 37.6 s

Explanation:

As we know that train is initially moving with the speed

v_i = 75.1 km/h

now we know that

v_i = 20.86 m/s

now the final speed of the train when it crossed the crossing

v_f = 15 km/h

v_f = 4.17 m/s

now we can use kinematics here

v_f^2 - v_i^2 = 2 a d

4.17^2 - 20.86^2 = 2 a(471)

a = -0.44 m/s^2

Now the time to cross that junction is given as

v_f - v_i = at

4.17 - 20.86 = a(-0.44)

t = 37.6 s

4 0
2 years ago
As the distance between two charged objects increases, the strength of the electrical force between the objects
AveGali [126]

As the distance between two charged objects increases, the strength of the electrical force between the objects  <em>decreases</em>.

7 0
3 years ago
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