Answer: 1.8
Explanation:
You are given
the object distance U = 24.8 cm
Focal length F = 16.0 cm
First find the image distance by using the formula:
1/f = 1/u + 1/v
Where V = image distance
Substitute u and f into the formula
1/16 = 1/24.8 + 1/v
1/ v = 1/16 - 1/24.8
1/v = 0.0625 - 0.04032258
1/v = 0.022177
Reciprocate both sides by dividing both sides by one
V = 45.09 cm
Magnification M is the ratio of image distance to the object distance. That is,
M = V/U
Substitute V and U into the formula
M = 45.09/24.8
M = 1.818
Magnification of the image is therefore equal to 1.8 approximately
Its just Calcium Flouride because as you can see it is an Ionic bond (Ca is metal and fl is a gas usually)
Answer:
no sabo por q no mi entender
Answer:
KE = 100 J
Explanation: Should be correct
<span>The line that is drawn perpendicular to the point at which a wave intersects a boundary is know as the Normal .
When the normal is drawn, the incident ray makes an angle with it known as the angle of incidence and the reflected ray makes an angle with it known as the angle of incidence. These angles are always equal.
The refracted ray makes an angle with the normal known as angle of refraction. The sin of angle of incidence to the sin of angle of refraction is called the refractive index( </span>μ= <span>sin i / sin r) .
hope all of it helps you!</span>
