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AveGali [126]
2 years ago
6

The freezing point of an aqueous 0.050 m cacl2solution is −0.27 °c. what is the van’t hoff factor (i) for cacl2at this concentra

tion? how does it compare to the expected value of i?
Physics
1 answer:
Andru [333]2 years ago
3 0

Then the answer is 2.9

$\begin{aligned} \Delta T_{f} &=i \times m \times k_{f} \\ i &=\frac{\Delta T_{f}}{m \times k_{f}} \end{aligned}$

=\frac{0.27^{\circ} \AC}{0.050 \times  \frac{1.86^{\circ} \mathrm{C}}{\mathrm{m}}}

\therefore i^{2}=2.9

Using van’t hoff factor the answer has no unit, as, expected since i is a ratio. The magnitude is about right since it is close to the value ace would expect upon the complete dissociation $\mathrm{CaCl}_{2}$.

What is Van't Hoff factor?

  • The Van't Hoff factor is always positive and can never be negative. When the solute remains completely undissociated in solution, the Van't Hoff factor is one; it is greater than one for salts and acids and less than one for the solute that associates when dissolved to form a solution.
  • The van't Hoff factor is defined as the ratio of the observed colligative property produced by a given concentration of electrolyte solution to the observed colligative property produced by the same concentration of non-electrolyte solution.

To learn more about van't Hoff factor visit: brainly.com/question/24598605

#SPJ4

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A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

5 0
3 years ago
How far does a boat travel in 5 hours at 32 miles per hour? 162 mi 160 mi 210 mi
sleet_krkn [62]
We know that:
d=vt
d=32mph*5h
d=160mi
4 0
3 years ago
Read 2 more answers
Recent findings on the topic of brain based research indicate all of the following except
Gre4nikov [31]
The answer is D, the brain actually stops growing around age 18
5 0
3 years ago
A slide with an image 4cm×2cm is placed at a distance of 10 cm behind a converging lens and a clear image is formed on a screen
pav-90 [236]

Answer:

44cm x 22cm

Explanation:

u= 10 cm

v= 1.1 cm

m=v/u= 1.1/10

m=11

hence the size of the image.

7 0
2 years ago
What is the kinetic energy of a golf ball with a mass of 0.046 kg traveling at 15.5<br> m/s?
Serjik [45]

Answer:

<h2>5.53 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 0.046 \times {15.5}^{2}  \\  = 0.023 \times 240.25 \\  = 5.52575

We have the final answer as

<h3>5.53 J</h3>

Hope this helps you

3 0
3 years ago
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