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Zolol [24]
2 years ago
15

Find the volume. I need this in now like ASAP 10 points

Mathematics
2 answers:
Tom [10]2 years ago
8 0

Answer:

0.48 m^3

Step-by-step explanation:

volume = length * breadth * height

=6m * 4m * 0.02m

=0.48 m^3

adell [148]2 years ago
4 0
Volume is 0.48 im 99% sure cause the formula is lwh
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-7X&gt;10<br>solve for x answer musr be simplifyed<br>​
Scrat [10]

Answer:

x < -10/7

Step-by-step explanation:

Divide both sides by -7.  Because this divisor is negative, we must reverse the direction of the inequality sign, obtaining:

-7x   <   10

-----   <  -----

 -7         -7

Then x < -10/7

8 0
3 years ago
******Please help me help please help me ******
Veseljchak [2.6K]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
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What does 125 have in common with a^3 when 125 is written as a power?
mestny [16]

125

2

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Rewrite  

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125

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5

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25

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3 years ago
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Helpp my grades are almost dueeeeeeee,,, but anyway hows yall dayyy?
tekilochka [14]
C is the. Answer as you multiply by -1/3
3 0
2 years ago
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The auto parts department of an automotive dealership sends out a mean of 4.2 special orders daily. What is the probability that
gregori [183]

The probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

<h3>What are some of the properties of Poisson distribution?</h3>

The Poisson distribution is a discrete probability distribution that describes the likelihood of a specific number of events occurring in a specified span of time or space, if these events occur at a constant mean rate and regardless of the time since the last occurrence.

Let X ~ Pois(λ)

Then we have:

E(X) = λ = Var(X)

Since standard deviation is the square root (positive) of variance,

Thus,

The standard deviation of X = \sqrt{\lambda}

Its probability function is given by

f(k; λ) = Pr(X = k) =   \dfrac{\lambda^{k}e^{-\lambda}}{k!}

Given the mean is 4.2.

We have to find the probability that on any day, the number of special orders sent out will be exactly 3. Therefore, the value of x will be 5.

Using the Poisson distribution,

P(x) = \dfrac{e^{-\lambda}\lambda ^x}{x!}\\\\P(5) =\dfrac{e^{-4.2}(4.2)^5}{5!}\\\\P(5) = 0.1633

Hence, the probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

Learn more about Poisson distribution here:

brainly.com/question/7879375

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