Elements with atomic numbers above 95 are called ____

The magnitude of the charge of the electron is:

brilliants [131]

Answer:

a. Exactly the same as the magnitude of the charge of the proton.

Explanation:

The elementary charge (e) is the smallest electric charge that can exist in the universe. Any positive or negative electric charge can be expressed as a multiple of the elementary charge, since is the electric charge carried by a single proton or, equivalently, the magnitude of the electric charge carried by a single electron (-1e).

3 0

4 years ago

A battery of 1 V gives how much energy to each Coulomb of charge? A. Not enough info B. 5 Joules C. 1 Joule D. 0.5 Joules

Artist 52 [7]

C. 1 Joule

Explanation:

Given:

Voltage = 1V

Quantity of charge = 1coulomb

Unknown:

Energy = ?

Solution:

The amount of work done is often related to the energy in a system.

In this electrical circuit, work done is the voltage that moves a particular charge.

work done = q x v

q is the quantity of charge

v is the voltage

the potential difference in circuit is the driving force of charges.

Work done = energy = qv

inputting the parameters;

Work done = 1 x 1 = 1J

learn more:

Electrochemistry problems brainly.com/question/6953278

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5 0

3 years ago

8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bott

nasty-shy [4]

Answer: The ball is travelling with a speed of 5.5 m/s after hitting the bottle.

Explanation:

To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of ball.

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of bottle.

We are given:

$m_1=0.4kg\\u_1=18m/s\\v_1=?m/s\\m_2=0.2kg\\u_2=0m/s\\v_2=25m/s$

Putting values in above equation, we get:

$(0.4\times 18)+(0.2\times 0)=(0.4\times v_1)+(0.2\times 25)\\\\v_1=5.5m/s$

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.

5 0

3 years ago

How much heat is released when 12.0 grams of helium gas condense at 2.17 K? The latent heat of vaporization of helium is 21 J/g.

uranmaximum [27]

To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released

8 0

3 years ago

Read 2 more answers

A 2.0 kg tumor is being irradiated by a radioactive source.The

navik [9.2K]

Answer:

426136363636.36365 Bq

Explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

$Activity=\dfrac{Grays\times Mass}{Time\times 0.4}\\\Rightarrow Activity=\dfrac{12\times 2}{880\times 0.4\times 1.6\times 10^{-13}}\\\Rightarrow Activity=426136363636.36365\ Bq$

The activity N//t of the radioactive source is 426136363636.36365 Bq

6 0

4 years ago

Elements with atomic numbers above 95 are called _____ elements