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Law Incorporation [45]
3 years ago
12

A student uses a magnet to move a 0.0 25 KG metal ball the magnet exerts a force of five in which causes the body to begin movin

g what is the acceleration of the ball when it begins to move
Chemistry
1 answer:
givi [52]3 years ago
7 0

Answer:

The acceleration of the ball when it begins to move is 200 m/s²

Explanation:

The given parameters are;

The mass of the metal ball, m = 0.025 kg

The force exerted by the magnet on the ball, F = 5 N

From Newton's second law, F = m × a

Where;

a = The acceleration of the ball

Therefore, by substitution, we have;

5 = 0.025 × a

a = 5/0.025 = 200 m/s²

The acceleration of the ball when it begins to move = 200 m/s²

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what is the difference between a chemical bonds formed in the molecules of 02 and the chemical bonds formed in crystals of a NaC
Jobisdone [24]

Answer:

O2 is a covalent substance while NaCl is an ionic substance

Explanation:

In O2 molecule, the bond is between 2 oxygen atoms which are non - metals. Thus, this is a covalent bond since it involves 2 non metals.

Whereas, for the NaCl molecule, the bond is between a metal sodium (Na) and a non metal Chloride(Cl) and thus we can say this is an ionic bond.

Thus the difference is that O2 is a covalent substance while NaCl is an ionic substance.

8 0
3 years ago
Picture has the question
xenn [34]

Answer:I believe it is 5

Explanation:

8 0
4 years ago
Read 2 more answers
Balance the following equation;C<img src="https://tex.z-dn.net/?f=C5H12%28g%29%2BO2%28g%29%3DC02%28g%29%2BH2O%28l%29" id="TexFor
Bumek [7]

put 8 in front of the oxygen in the reactants side to make it 16 molecules then put a 5 in front of the co2 in the product side to balance the carbon atoms then put a 6 in front of the H20 on the product side this balances both the hydrogen and oxygen atoms here is a representation

C5H12(g)+8O2(g)=5CO2(g)+6H20

4 0
2 years ago
1.
Mazyrski [523]

1)   {ca}^{2 + }  = cation \\ {br}^{2 - }  = anion

7 0
3 years ago
Read 2 more answers
In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?
Mashutka [201]
Molar mass :

NaBr = 103 g/mol

Pb(NO3)2 = 331.20 g/mol

<span><span /><span>Balanced chemical equation :

</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
      g NaBr  -------------------> 311 g Pb(NO3)2

331.20  g  =   2*103*311

331.20 g = 64066

mass ( NaBr ) =  64066 / 331.20

mass ( naBr)  = 193,43 g of NaBr

hope this helps!.


</span>
5 0
3 years ago
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