Answer:
0.0295M
Explanation:
As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.
You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.
That means you are diluting your solution 95.0mL / 35.0mL = 2.714 times.
And the concentration of SCN⁻ is:
0.0800M / 2.714 =
<h3>0.0295M </h3>
Answer:
electrophile(H⁺) is needed to react with alkene in the first step and nucleophile (OH⁻) is not available in the first step
Explanation:
Answer:
6.43 moles of NF₃.
Explanation:
The balanced equation for the reaction is given below:
N₂ + 3F₂ —> 2NF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.
Thus, 6.43 moles of NF₃ were obtained from the reaction.
Mg3(AsO4)2
Ca(ClO4)2
[S (II) not sure]
[F (I) not sure]
PO₄³
Sorry I don’t know all of them, good luck though! :)
Answer:
30 hot dogs
Explanation:
It is given that :
There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners
There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns
One hot dogs need 1 bun and 1 wiener to make a hot dog.
There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.
Therefore, 30 hot dogs.
And the number of extra wieners left = 32 - 30 = 2 wieners.
