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Otrada [13]
3 years ago
8

Forces cause changes to the motion of objects. Name a force and describe two changes it makes.

Physics
1 answer:
otez555 [7]3 years ago
3 0
Sliding and Static.

Would be the right one here.
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The sizes of most of the cells our bodies are about A.1micrometer
Alekssandra [29.7K]

Answer:

1Mm

Explanation:

i think this one. so it is wrong then also dont be angry with me because iam trying to help u

5 0
2 years ago
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I would like to know why this is the correct answer
Marta_Voda [28]

Answer:

see below

Explanation:

First, the obvious, as you press the gas pedal harder the acceleration goes up as well.  Conversely, is you do not press the pedal, you will not accelerate.  This determines that is I press the gas pedal, it will CAUSE the car to accelerate.  This proves causation.

Now, correlation.  The definition of correlation in statistics is any statistical relationship between two random variables or data.  This simply means that these two events are connected to one another.  A POSITIVE correlation is when two correlated events move in the same direction as one another.  I have added a graph to help visualize this.  In this problem as the gas is pressed harder, the acceleration increases.  If the pressure on the pedal was decreased, then the acceleration also decreases.  If the pressure on the pedal is constant, the the acceleration is constant.

I hope this helps!

4 0
3 years ago
When does a rubber band, which has been shot at a wall, have the most potential energy?
Yuri [45]
D When it is stretched ready to shoot at the wall
4 0
2 years ago
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A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
Two point charges, 1.8 pC and −1.8 pC, are separated by 7 µm. What is the dipole moment of this pair of charges?
Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C

Distance = 7 micrometer, is equal to 0.0000070m

From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.

Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm

NB: The charges are identical.

3 0
2 years ago
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