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Pavlova-9 [17]
3 years ago
12

Match each item with the correct statement below.

Chemistry
1 answer:
V125BC [204]3 years ago
5 0

1. LDFs

2. Intermolecular Forces

3. Intramolecular Forces

4. Linear

5. Tetrahedral

Edit: I'm new to this site and idk how to use it properly. I'm not sure about 2 and 3 currently because these forces are between molecules as well so INTERmolecular would be used twice (?)

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Which claim about cats is most likely based on science?
MrRissso [65]

Answer:D

Explanation:

4 0
3 years ago
Draw the correct structural formula for the following compounds:
Anvisha [2.4K]

Answer:

Explanation:

a) H3C-CH=CH-CH2-CH3

b)     CH3                     CH3

         |                           |

CH3-C-     CH- CH2-   CH-CH3

        |         |  

      C2H5  C2H5

c)                 C2H5

                    |

CH3-C=CH-CH-CH2-CH-CH3

         |                          |

        CH3                    CH3

6 0
4 years ago
A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.
hodyreva [135]

Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

m_1u_1+m_2u_2=m_1v_1+m_2v_2     ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of the first object.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

m_1=80.00kg\\m_2=0.16kg\\u_1=0m/s\\u_2=28m/s\\v_1=v_2=V=?m/s

Putting values in equation 1, we get:

80(0)+0.16(28)=(0.80+0.16)V

V=0.056m/s

The final velocity of man and hockey puck is 0.056 m/s.

6 0
3 years ago
Read 2 more answers
A sample of 9.27 g9.27 g of solid calcium hydroxide is added to 38.5 mL38.5 mL of 0.500 M0.500 M aqueous hydrochloric acid. Writ
navik [9.2K]

<u>Answer:</u> The excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.  

<u>Explanation:</u>

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ....(1)

<u>For calcium hydroxide:</u>

Given mass of calcium hydroxide = 9.27 g

Molar mass of calcium hydroxide = 74.093 g/mol

Putting values in above equation, we get:

\text{Moles of calcium hydroxide}=\frac{9.27g}{74.093g/mol}=0.125mol

  • To calculate the moles of a solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Volume of hydrochloric acid = 38.5mL = 0.0385 L   (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.500 moles/ L

Putting values in above equation, we get:

0.500mol/L=\frac{\text{Moles of hydrochloric acid}}{0.0385L}\\\\\text{Moles of hydrochloric acid}=0.01925mol

  • For the given chemical equation:

2HCl(aq.)+Ca(OH)_2(s)\rightarrow CaCl_2(s)+2H_2O(l)

Here, the solid salt is calcium chloride.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium hydroxide.

So, 0.01925 moles of hydrochloric acid will react with = \frac{1}{2}\times 0.01925=0.009625moles of calcium hydroxide.

As, given amount of calcium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

  • Amount of excess reagent (calcium hydroxide) left = 0.125 - 0.01925 = 0.115375 moles

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.01925 moles of hydrochloric acid will produce = \frac{1}{2}\times 0.01925=0.009625moles of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 110.98 g/mol

Moles of calcium chloride = 0.009625 moles

Putting values in equation 1, we get:

0.009625mol=\frac{\text{Mass of calcium chloride}}{110.98g/mol}\\\\\text{Mass of calcium chloride}=1.068g

Hence, the excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

5 0
3 years ago
Read 2 more answers
The easiest way to determine whether a process is exothermic or endothermic is to note the change in temperature in a calorimete
Kryger [21]

Answer:

In the calorimeter, water is the <u>exothermic</u>. The salt LiCI, which will dissolve, is the <u>endothermic</u>. The final temperature of the water after the dissolution of LiCI was <u>lower</u> than the initial temperature, meaning the process is <u>exothermic</u>. In the microscopic view of the disspolution of LiCI, water molecules were seen to move <u>slowly</u> as they <u>gained </u>energy.

Explanation:

Exothermic is a process in which heat is released during the process. Endothermic reactions absorbs heat from surrounding during a chemical process. The dissolution of salt into water is an exothermic reaction. During this process heat is release and water molecules are broken down which are surrounded by salt ions.

5 0
3 years ago
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