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3 years ago

Please help I will give you brainliest!!!!

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Answer:

63.25sqft

Step-by-step explanation:

semi circle:

a= $\pi$ r^2

a= $\pi$ (5)^2 (radius is 5 bc diameter is 10 so you divide it by 2)

a=25 $\pi$

a=78.5/2=39.25 (divide by 2 bc its a semi circle)

triangle:

a=1/2bh

a=1/2(6x8)

a=1/2(48)

a=24

area:

39.25+24=63.25

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Heyyy ummm... help??

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The statements true for the given function are:

$f(0) = \frac{3}{2}$
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I tried them all and these two were correct, their solutions are as follows:

= f(x) = 1/2x + 3/2

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3 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3>Solution:</h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

So we can frame a equation as:

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

Let us solve the above quadratic equation

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

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