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3 years ago

7

Please help I will give you brainliest!!!!

1 answer:

VikaD [51]3 years ago

8 0

Answer:

63.25sqft

Step-by-step explanation:

semi circle:

a= $\pi$ r^2

a= $\pi$ (5)^2 (radius is 5 bc diameter is 10 so you divide it by 2)

a=25 $\pi$

a=78.5/2=39.25 (divide by 2 bc its a semi circle)

triangle:

a=1/2bh

a=1/2(6x8)

a=1/2(48)

a=24

area:

39.25+24=63.25

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Z=5x- 11y <br> can someone please help

Feliz [49]

Answer:

z+11y/5 = x

Step-by-step explanation:

Since you are solving for x, you want to isolate the variable. You do that by adding 11y to both sides, which cancels out the -11y. From that you should have z+11y = 5x. To cancel out the 5x you need to divide both sides by 5 to get z+11y/5 = x. Hope this helps :)

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3 years ago

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andrew11 [14]

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3 years ago

WILL CHOOSE BRAINLIEST!!! The oxford square is approximately 300 feet on each side. What is the length of the diagonal square?

Marina CMI [18]

Answer:

424 ft and 3 inches

Step-by-step explanation:

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2 years ago

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Y = -3x + 5? *<br> What’s the slope of the equation y =-3x+5

Crazy boy [7]

Answer:

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3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

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3 years ago