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jeyben [28]
2 years ago
10

A student jumps of a sled toward the west after it stops at the bottom of an icy hill. Based on the law of action-reaction, in w

hat direction will the sled most likely move as the student jumps off
Chemistry
1 answer:
Delicious77 [7]2 years ago
3 0

Answer:

East

Explanation:

Given Newton's third law of motion; "Action and reaction are equal and opposite", when a student jumps off a sled toward the west after it stops at the bottom of an icy hill, the sled will move in the East direction.

This is because, the force exerted on the sled is a reaction force and is opposite in direction to the force that thrusts the boy westward though equal in magnitude with the former.

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List the elements and the amounts of each element below for 5 Li2S04.​
GREYUIT [131]

Answer:

Lithium has 5 elements, sulphur has 2 elements and oxygen has 4 elements

7 0
2 years ago
Which of the following is NOT how compounds are formed?
cricket20 [7]
Compounds are not formed by accepting electrons. Number 1 and 3 are correct.
5 0
3 years ago
Read 2 more answers
1 Mothers ages 8 years more than twice her daughter's
Anit [1.1K]
<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  We can use the information to form an equation, which we can solve later

M = 2x + 8

Simply substitute the daughter's age into x:

M = 2(56) + 8

Now solve:

M = 120

<h3><u>❄️</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
3 years ago
Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 3.56 mol of m
pishuonlain [190]
<h3>Answer:</h3>

43.27 g Mg

<h3>Explanation:</h3>

The balanced equation for the reaction between magnesium metal and hydrochloric acid is;

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)

From the equation;

1 mole of magnesium reacts with 2 moles of HCl

We are given;

3.56 moles of Mg and 3.56 moles of HCl

Using the mole ratio;

3.56 moles of Mg would react with 7.12 moles of HCl, and

3.56 moles of HCl would react with 1.78 moles of Mg

Therefore;

The amount of magnesium was in excess;

Moles of Mg left = 3.56 moles - 1.78 moles

                         = 1.78 moles

But; 1 mole of Mg = 24.305 g/mol

Therefore;

Mass of magnesium left = 1.78 moles × 24.305 g/mol

                                        = 43.2629 g

                                        = 43.27 g

Thus, the mass of magnesium that remained after the reaction is 43.27 g

4 0
3 years ago
You do an experiment in which you need 0.5 moles of tyrosine (C9H11NO3). How many grams must you weigh out?
Yuki888 [10]

Answer: a)  90.5g

b) 33.6 L

Explanation:-

Molar mass of tyrosine  (C_9H_{11}NO_3)= 181 g/mol

According to Avogadro's law, 1 mole of every substance weighs equal to its molar mass.

1 mole of tyrosine  (C_9H_{11}NO_3) weighs = 181 g/mol

0.5 moles of tyrosine  (C_9H_{11}NO_3) weigh =\frac{181g/mol}{1}\times 0.5moles=90.5g

b) According to Avogadro's law, 1 mole of an ideal gas occupies 22.4 Liters at Standard conditions of temperature and pressure (STP).

1 mole of gas at STP occupy = 22.4 L

1.5 moles of gas at STP occupy =\frac{22.4L}{1}\times 1.5=33.6L



5 0
2 years ago
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