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klasskru [66]
4 years ago
13

Be sure to show all 4 steps for each of the problems below.

Physics
1 answer:
Kisachek [45]4 years ago
7 0

Answer:

1=920

2=2300

Explanation:

from the question,

M¹=23

H¹=4

g=10(constant)

using the formula

P. E,= mgh

P. E= 23×10×4=920

P. E=23×10×10=2300

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According to Mendel's law of segregation, what takes place during meiosis?A.Pairs of alleles cross over on chromosomes, exchangi
inysia [295]

Answer:

b. Pairs of alleles separate in meiosis, and each gamete receives one allele of a pair.

Explanation:

Gregor Mendel, who is referred to as the FATHER OF GENETICS because of his contribution to the principles of inheritance, proposed in one of his laws called LAW OF SEGREGATION that the alleles of a gene will separate into gametes in such a way that only one of the two alleles that make up a gene will be in each gamete.

This division/separation of alleles during gamete formation is called MEIOSIS. Note that, allele is one member of a gene. Hence, according to Mendel, in meiosis, pairs of alleles separate and each gamete receives one allele of a pair.

5 0
3 years ago
Meaning of power in physics
zmey [24]

Answer:

The rate of doing work is called power.

4 0
3 years ago
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What happens during the fall in September?
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Answer:

During the fall in September, the Sun passes from northern hemisphere towards equator. ... On this day, Sunlight directly falls on the equator i.e. the sun crosses celestial equator. Day time is equal to night time in the two hemispheres

Explanation:

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3 years ago
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A 6.00-kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
timofeeve [1]

Answer:

The magnitude of F when t=4 s=146.64 N

Explanation:

We are given that

Mass of crate,m=6.00 kg

Height of crate above its initial position is given by

y(t)=(2.80 m/s)t+(0.610 m/s^3)t^3

We have to find the magnitude of F when t=4.00 s

Differentiate w.r.t t

\frac{dy}{dt]=2.8+3(0.61)t^2

\frac{d^2y}{dt^2}=6(0.61)t

a(t)=\frac{d^2y}{dt^2}=6(0.61)t m/s

a(4)=6(0.61)(4)=14.64 m/s^2

Now, magnitude of force

F=m(a+g)=6(14.64+9.8)=146.64N

Hence, the magnitude of F when t=4 s=146.64 N

4 0
3 years ago
The charge entering the positive terminal of an element is q = 5 sin 4πt mC while the voltage across the element (plus to minus)
Artemon [7]

Answer:

(a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

Explanation:

Given that,

Charge q=5\sin4\pi t\ mC

Voltage v=3\cos4\pi t\ V

Time t = 0.3 sec

We need to calculate the current

Using formula of current

i(t)=\dfrac{dq}{dt}

Put the value of charge

i(t)=\dfrac{d}{dt}(5\sin4\pi t)

i(t)=5\times4\pi\cos4\pi t

i(t)=20\pi\cos4\pi t

(a).We need to calculate the power delivered to the element

Using formula of power

p(t)=v(t)\times i(t)

Put the value into the formula

p(t)=3\cos4\pi t\times20\pi\cos4\pi t

p(t)=60\pi\times10^{-3}\cos^2(4\pi t)

p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi t}{2})

Put the value of t

p(t)=60\pi\times10^{-3}(\dfrac{1+\cos8\pi\times0.3}{2})

p(t)=30\pi\times10^{-3}(1+\cos8\pi \times0.3)

p(t)=187.68\ mW

(b). We need to calculate the energy delivered to the element between 0 and 0.6 s

Using formula of energy

E(t)=\int_{0}^{t}{p(t)dt}

Put the value into the formula

E(t)=\int_{0}^{0.6}{30\pi\times10^{-3}(1+\cos8\pi \times t)}

E(t)=30\pi\times10^{-3}\int_{0}^{0.6}{1+\cos8\pi \times t}

E(t)=30\pi\times10^{-3}(t+\dfrac{\sin8\pi t}{8\pi})_{0}^{0.6}

E(t)=30\pi\times10^{-3}(0.6+\dfrac{\sin8\pi\times0.6}{8\pi}-0-0)

E(t)=57.52\ mJ

Hence, (a). The power delivered to the element is 187.68 mW

(b). The energy delivered to the element is 57.52 mJ.

6 0
3 years ago
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