Answer:
4.02 s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 35°
Initial velocity (u) = 50 m/s
Acceleration due to gravity (g) = 10 m/s²
Time of flight (T) =?
The time of flight of the arrow can be obtained as follow:
T = 2uSineθ / g
T = 2 × 35 × Sine 35 / 10
T = 70 × 0.5736 / 10
T = 7 × 0.5736
T = 4.02 s
Therefore, the time taken for the arrow to return is 4.02 s
Answer:
towards the south
Explanation:
When the electron enters the region with magnetic field, it experiences a magnetic force perpendicular to both the directions of the electron's velocity and the magnetic field.
The direction of the force exerted on the electron can be found by using the right-hand rule:
- Index finger: direction of the velocity of the electron --> towards the east
- Middle finger: direction of the magnetic field --> downward
- Thumb: direction of the force on a positive particle --> towards the north
However, the electron is a negatively charged particle, so we must reverse the direction of the force: therefore, the force exerted on the electron is towards the south.
Answer:
The period of the pendulum will increase.
Explanation:
The period of the pendulum will increase since g efective will decrease.
Then g efective is given by
g efective = g - a < g
If ⇒ T = 2π√(L/g)
and T' = 2π√(L/(g - a))
then T < T'
When the elevator accelerates downward, the hanging mass feels “lighter” – this means that the effective value of g has decreased due to the acceleration of the elevator. Since the period depends inversely on g, and the effective value of g decreased, then the period of the pendulum will increase
.
(i.e., its frequency will decrease and it will swing slower)
yup they r equal as mentioned above is equal magnitude and direction! so they r totally equal.
as one vector has 2 things which is used to define it ->
- Magnitude
- direction
so if both r equal then both vectors r equal vectors
Explanation:
Let u is the initial speed of the bike. Finally, the bike stops, v = 0
Deceleration of the bike, 
Time, t = 5
Distance covered, s = 62.5 m
We need to find the initial speed of the bike. Using third equation of motion as :
u = 11.18 m/s
So, the initial speed of the bike is 11.18 m/s. Hence, this is the required solution.
