Two point charges are separated by 6.4 cm . The attractive force between them is 10 N . Suppose that the charges attracting each
1 answer:
You might be interested in
Answer:
The velocity of the 4.00 kg object after the collision is 12 m/s.
Explanation:
Given that,
Mass of object
Velocity of object
Mass of another object
Velocity of another object
We need to calculate the relative velocity
The relative velocity is 8 m/s in west before collision.
We know that,
In one dimensional elastic collision, the relative velocity before collision equals after collision but with opposite sign.
So, The relative velocity after collision must be 8 m/s in east.
So, The object of 6.00 kg is going 20 m/s and the object of 4.00 kg is slows down to 12 m/s.
Hence, The velocity of the 4.00 kg object after the collision is 12 m/s.