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matrenka [14]
3 years ago
13

4) Calculate the heat needed to melt 40.0 g of ice at 0°C?

Chemistry
1 answer:
Sav [38]3 years ago
3 0
A lot of heat like a lot no cap it’s gonna he a lot
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Old but good do a volcano <span />
4 0
3 years ago
Read 2 more answers
Which of the following is true of gas?
lesantik [10]

Answer:

Gases mix easily because of their high kinetic energy and low inter-molecular forces.

Explanation:

8 0
3 years ago
Do parts a, b and c
Leona [35]

Answer:- (a)The pH of the buffer solution is 3.90.

(b) the pH of the solution after addition of HCl would be 3.60.

(c) the pH of the buffer solution after addition of NaOH is 4.32.

Solution:- (a) It is a buffer solution so the pH could easily be calculated using Handerson equation:

pH=Pka+log(\frac{base}{acid})

pKa can be calculated from given Ka value as:

pKa=-logKa

pKa=-log(6.3*10^-^5)

pKa = 4.20

let's plug in the values in the Handerson equation:

pH=4.20+log(\frac{0.025}{0.05})

pH = 4.20 - 0.30

pH = 3.90

The pH of the buffer solution is 3.90.

(b) Let's say the acid is represented by HA and the base is represented by A^- .

Original mili moles of HA from part a = 0.05(100) = 5

original mili moles of A^- from part a = 0.025(100) = 2.5

mili moles of HCl that is H^+ added = 0.100(10.0) = 1

This HCl reacts with the base present in the buffer to make HA as:

A^-+H^+\rightarrow HA

Total mili moles of HA after addition of HCl = 5+1 = 6

mili moles of base after addition of HCl = 2.5-1 = 1.5

Let's plug in the values in the Handerson equation again. Here, we could use the mili moles to calculate the pH. The answer remains same even if we use the concentrations also as the final volume is same both for acid and base.

pH=4.20+log(\frac{1.5}{6})

pH = 4.20 - 0.60

pH = 3.60

So, the pH of the solution after addition of HCl would be 3.60.

(c) mili moles of NaOH or OH^- added to the original buffer = 0.05(15.0) = 0.75

This OH^- reacts with HA to form A^- as:

HA+OH^-\rightarrow H_2O+A^-

mili moles of HA after addition of NaOH = 5-0.75 = 4.25

mili moles of A^- after addition of NaOH = 2.5+0.75 = 3.25

Let's plug in the values again in Handerson equation:

pH=4.20+log(\frac{3.25}{4.25})

pH = 4.20 - 0.12

pH = 4.32

So, the pH of the buffer solution after addition of NaOH is 4.32.

7 0
3 years ago
a sample of mass 6.814grams is added to another sample weighing 0.08753 grams. the subsequent mixture is then divided into exact
Alexxx [7]

Answer:

Final\ Mass = 17.560943085g

Explanation:

Given

Sample\ Mass = 6.814g

Additional\ Mass = 0.08753g

Yield = 7.6335

Required

Determine the final mass

First we need to determine the total mass after the sample mass is added to an additional sample;

Total\ Mass = Additional\ Mass + Sample\ Mass

Total\ Mass = 0.08753g + 6.814g

Total\ Mass = 6.90153g

Next, divide the total mass by 3

New\ Mass = \frac{Total\ Mass}{3}

New\ Mass = \frac{6.90153g}{3}

New\ Mass = 2.30051g

The final mass is calculated as follows;

Final\ Mass = New\ Mass * Yield

Final\ Mass = 2.30051g * 7.6335

Final\ Mass = 17.560943085g

<em>Hence, the final mass is 17.560943085g</em>

6 0
3 years ago
When aluminum, Al, metal is dipped in an aqueous solution of hydrochloric acid, HCl, hydrogen gas H_2 is produced with the forma
erica [24]

Answer:

2Al(s) + 6HCl(aq) = 2AlCl3(aq) + 3H2(g)

Explanation:

The reaction is a displacement reaction.

The reaction does not commence immediately because the Al(aluminum) has Al2O3 (Aluminum oxide) which protect it from reacting with water.

It takes some time for the HCl (hydrochloric acid) to eat the coating, then the reaction proceed vigorously to produce hydrogen gas bubbles. Generally metals that are above hydrogen in the electrochemical series tend to displace Hydrogen from Hydrochloric acid. The more negative the electrochemical volts the more the tendency to lose electron. Metal above hydrogen have negative evolts while those below have positive evolts

3 0
3 years ago
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