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beks73 [17]
3 years ago
13

Please anwser fast it’s due in 5 minutes

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer:30000 just 5000+  six time

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F(x) = 2x<br> g(x) = 2x + 1<br> Find<br> (f/g) (x) . Include ahy restrictions on the domain.
victus00 [196]

Answer:

quotient is 1 and remainder is -1

Step-by-step explanation:

\frac{f(x)}{g(x)}

_1_______________

2x+1 | 2x

- 2x + 1

___________

-1

7 0
3 years ago
What is the simplest form of the expression?
Vitek1552 [10]
2a^3b^2(cube root of) 4a
6 0
4 years ago
In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa
Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434

Hence, the required number of ways =27434

5 0
3 years ago
Can someone help me please
tamaranim1 [39]

all shapes with 4 angles are 360 degrees

100+96= 196

360-196= 164

c+d=164

80+84=164

D is 84

C is 80

4 0
3 years ago
Read 2 more answers
3. Reason quantitatively. A figure has vertices P(-3, 1), Q(9, 1), R(3, —7), and S(-9, -7).
BlackZzzverrR [31]
Don’t listen to them
3 0
3 years ago
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