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Gennadij [26K]
3 years ago
7

Help help chem question

Chemistry
1 answer:
Sonbull [250]3 years ago
6 0

Answer:

I think it is E or C

Explanation:

If you multiply E out the result is 530,000,000 which is higher than the rest. If not that than I think it is C, one of the two.

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The products of a neutralization reaction are ________ and ________ a salt.
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Explanation:

Neutralization reaction is a type of chemical reaction in which an acid and a base react together to form a salt <u><em>and water</em> </u>as products.

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3 years ago
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Combining 0.381 mol of Fe2O3 with excess carbon produced 17.4 g of Fe.
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What happens to Kinetic?<br> energy during gas particles collision
Vitek1552 [10]

Answer:

Gas particles are in a constant state of the  random motion and move in straight lines until they collide with another body. The collisions exhibited by gas particles are completely elastic; when the two molecules collide, total kinetic energy is conserved.

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3 years ago
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Someone help it’s due today
Kitty [74]

Answer:

All elements are neutral

Explanation:

The plum pudding model of the atom indicated that all elements are neutral. The model was proposed by J.J Thomson after he conducted his experiment on the gas discharge tube.

From the experiment he discovered electrons which he called cathode rays.

Therefore, he suggested the plum pudding model of the atom.

The model describes negatively charge sphere surrounded by positive charges to balance them.

6 0
3 years ago
Calculate the volume in liters of a 1.60 mol/L sodium nitrate solution that contains of sodium nitrate . Round your answer to si
Whitepunk [10]

Answer:

1.5L of NaNO3 must be present

Explanation:

<em>That contains 200g of sodium nitrate. Round to 2 significant digits</em>

To solve this question we need to convert the mass of NaNO3 to moles using its molar mass (85g/mol). With the moles and the molar concentration we can find the volume in liters of the solution:

<em>Moles NaNO3:</em>

200g * (1mol / 85g) = 2.353 moles NaNO3

<em>Volume:</em>

2.353 moles NaNO3 * (1L / 1.60moles) =

<h3>1.5L of NaNO3 must be present</h3>
7 0
3 years ago
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