Answer:
From the equation you will see that 1 mol of propane generates 4 mols of water.
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
Explanation:
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
Answer: it should be in your reference table
I don’t have an earth science table with me but it is a whole page of wind belts
Explanation:
Answer:
104.352°C
Explanation:
Data Given:
Boiling point of water = 100.0°C
Kb (boiling point constant = 0.512°C/m
Concentration of the Mg₃(PO₄)₂ = 8.5 m
Solution:
Formula Used to find out boiling point
ΔTb = m.Kb . . . . . . (1)
where
ΔTb = boiling point of solution - boiling point of water
So,
we can write equation 1 as under
ΔTb = Tb (Solution) -Tb (water)
As we have to find out boiling point so rearrange the above equation
Tb (Solution) = m.Kb + Tb (water) . . . . . . . (2)
Put values in Equation 2
Tb (Solution) = (8.5 m x 0.512°C/m ) + 100.0°C
Tb (Solution) = 4.352 + 100.0°C
Tb (Solution) = 104.352°C
so the boiling point of Mg₃(PO₄)₂ 8.5 m solution = 104.352°C
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. This is because the bond distance in methyl bromide is more due to the large size of bromine atom.
Dipole moment is calculated by multiplying the charge on the atom with the bond distance.
Answer:
For the reaction CH3COOH→CH3COO– + H+
Among the given statements which is the correct statement?
CH3COOH is a Brønsted-Lowry base.
CH3COO– is an Arrhenius base.
CH3COOH is a Brønsted-Lowry acid.
CH3COO– is a Lewis base.
Explanation:
Bronsted acid is the proton donor.
Bronsted base is the proton acceptor.
Arrhenius base is the one that releases OH- ions when dissolved in water.
Lewis base is the one that is an electron-pair donor.
In the given reaction,
CH3COOH→CH3COO– + H+
Acetic acid releases a proton.
So, it is a proton donor.
Hence, It is a Bronsted-Lowry acid.
Third option is the correct answer.