There's 6 because it says CH(3)F which means theres three hydrogen atoms in one, which tells us there's six in two
Answer:
The vegetable oils are liquid at room temperature. They contain double bonds. During hydrogenation double bonds break hydrogen is introduced and form vegetable ghee.
Explanation:
Hydrogenation:
It is the chemical process in which hydrogen is introduced in unsaturated hydrocarbons in the presence of catalyst Ni.
Simple hydrogenation reaction:
H₂C = CH₂ + H₂ → CH₃-CH₃
Ni
Hydrogenation is used on industrial level in the production of vegetable ghee.
The unsaturated hydrocarbons, fatty acids undergoes hydrogenation and form ghee.
The vegetable oils are liquid at room temperature. They contain double bonds. During hydrogenation double bonds break hydrogen is introduced and form vegetable ghee.
Answer:
CH₃NH₃⁺ is a weak acid.
HPO₄²⁻ has a negligible acidity.
CH₄ has a negligible acidity.
HNO₂ is a weak acid.
Explanation:
There are 7 strong acids: HCl, HBr, HI, HNO₃, H₂SO₄, HClO₃, HClO₄. The rest of the acids are weak.
CH₃NH₃⁺ is a weak acid, according to the following equation:
CH₃NH₃⁺ ⇄ CH₃NH₂ + H⁺
HPO₄²⁻ can act as an acid or as a base:
<u>Acid reaction:</u> HPO₄²⁻ ⇄ PO₄³⁻ + H⁺
<u>Basic reaction:</u> HPO₄² + H₂O ⇄ H₂PO₄⁻ + OH⁻
Given Kb > Ka, HPO₄²⁻ has a negligible acidity.
CH₄ cannot release nor accept H⁺ so it has a negligible acidity.
HNO₂ is a weak acid, according to the following reaction:
HNO₂ ⇄ H⁺ + NO₂⁻
Answer:
ΔH = -55.92 kJ
Explanation:
<u>Step 1:</u> Data given
1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water
After mixing the temperature rises to 83 °C
Specific heat of the solution = 4.184 J/g °C
Molar mass of NaOH = 40 G/mol
Molar mass of HBr = 80.9 g/mol
<u>Step 2: </u>The balanced equation
NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)
<u>Step 3:</u> mass of NaOH
Mass = moles * Molar mass
Mass NaOH = 1 * 40 g/mol
Mass NaOH = 40 grams
Step 4: Mass of HBr
Mass HBr = 1 mol * 80.9 g/mol
Mass HBr = 80.9 grams
Step 5: Calculate ΔH
ΔH = m*c*ΔT
ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)
ΔH= 220.9 * 4.184 * 60.5
ΔH= 55916.86 J = 55.92 kJ
Since this is an exothermic reaction, the change in enthalpy is negative.
ΔH = -55.92 kJ
Answer:
Multiply 3 by Avogadro's number.
Explanation:
The mole can be defined as the amount of a substance that contains Avogadro’s number of particles, 6.02 x 10²³.
For elementary particles:
Number of particles=
number of moles x 6.02 x10²³
From the question,
Number of moles = 3moles
Number of particles = 3 x 6.02 x10²³
