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Elis [28]
3 years ago
11

Help ASAP pleaseeee thank you

Chemistry
1 answer:
Artyom0805 [142]3 years ago
8 0
The correct answer is B. balance
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How many grams of water are produced when 4.50 L of
MA_775_DIABLO [31]

The answer for the following problem has been mentioned below.

  • <em><u>Therefore the mass of the water is 5.802 grams.</u></em>

Explanation:

Given:

volume of oxygen (V) = 4.50 L

Temperature (T) = 425 K

pressure of oxygen (P) = 2.50 atm

Gram molecular mass of oxygen (M) = 16.0 grams

To calculate:

mass of water (m)

We know;

According to the ideal gas equation;

     P × V = n × R × T

As we know;

no of moles = \frac{m}{M}

m represents the mass of oxygen (m)

M represents the Gram molecular mass (M)

According to above mentioned equation;

           P × V = n × R × T

P represents the pressure of the oxygen

V represents the volume of the oxygen

n represents the no of moles of the oxygen

R represents the universal gas constant

where,

the value of R is 0.0821 L atm/K moles

Substituting the values in the above equation;

                  2.50 × 4.50 = \frac{m}{16.0} × 0.0821 × 425

                   11.25 =  \frac{m}{16.0} × 34.8925

                  180 = m × 34.8925

                  m = \frac{180}{34.8925}

                  m = 5.158 grams

Therefore the mass of the of oxygen is 5.158 grams

Now;

As we know;

           \frac{m_{1} }{M_{1} } = \frac{m_{2} }{M_{2} }

where;

m_{1} represents the mass of the oxygen

M_{1} represents the gram molecular mass of the oxygen

m_{2} represents the mass of the water

M_{2} represents the gram molecular mass of water

    From the above given formula,

      \frac{5.158}{16.0} = \frac{m_{2} }{18}

where;

Gram molecular weight of water = 18.0 u

    m_{2} = 5.802 grams

<em><u>Therefore the mass of the water is 5.802 grams.</u></em>

5 0
3 years ago
How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined
insens350 [35]
Oxidation  half  reaction  is  written   as    follows when  using  using  reduction potential  chart
example  when  using  copper  it is  written  as  follows
CU2+   +2e-  --> c(s)  +0.34v
 oxidasation  is the  loos  of  electron  hence copper oxidation  potential  is  as  follows
cu (s)  -->  CU2+   +2e    -0.34v

7 0
3 years ago
Read 2 more answers
An aqueous solution contains 1.00 g/L of a derivative of the detergent laurel alcohol. The osmotic pressure of this solution is
iVinArrow [24]

Answer:

mm = 1043.33 g/mol

Explanation:

osmotic pressure (π):

  • π = CbRT

∴ π = 17.8 torr = 0.0234 atm

∴ Cb: solute concentration

∴ T = 25°C = 298 K

∴ R = 0.082 atm.L/K.mol

⇒ Cb = π/RT

⇒ Cb = (0.0234 atm)/((0.082 atm.L/K.mol)(298 K))

⇒ Cb = 9.585 E-4 mol/L

molar mass (mm):

⇒ mm = (1.00 g/L)(L/9.585 E-4 mol)

⇒ mm = 1043.33 g/mol

7 0
3 years ago
Small molecules that bind with self-proteins to produce antigenic substances are called ________. Small molecules that bind with
Leona [35]

Answer:

Haptens.

Explanation:

Haptens are known as small molecules that help to stimulate the production of antibody molecules when attached with a large molecule known as a carrier molecule such as proteins.

Haptens are used to study the mechanism of inflammatory bowel disease to help induce the autoimmune type of responses and allergic contact dermatitis.

4 0
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Purple Group Header Warm-Up Why can I smell a chocolate bar even though it is a solid? Read the description of the office myster
likoan [24]

Answer:

The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas

Explanation:

There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.

These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.

For example, 3 methylbutanal, vanillin, and several organic compounds which are known to be readily volatile.

4 0
3 years ago
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