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alekssr [168]
3 years ago
14

These are my dream cars there is more but it will only let me put 5

Engineering
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

niceeeeeeeeeeeeeeeeeee

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A computer can function without peripheral devices.<br><br> true <br><br> false
Rudiy27

Answer:false

Explanation:

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4 years ago
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Crank OA rotates with uniform angular velocity 0  4 rad/s along counterclockwise. Take OA= r= 0.5
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3 years ago
A rear wheel drive car of mass 1000 kg is accelerating with a constant acceleration without slipping from 0 to 60 m/s in 1 min.
tester [92]

Answer:

500 N

Explanation:

Given;

Mass of the car, M = 1000 kg

initial speed of the car, u = 0 m/s

Final speed of the car, v = 60 m/s

Time, t = 1 min = 60 s

Now,

Force, F is given as:

F = Ma

where,

a is the acceleration

From the Newton's equation of motion, we have

v = u + at

on substituting the values, we get

60 = 0 + a × 60

or

a = 1 m/s²

Thus,

Force = 1000 × 1 = 1000 N

now,

this force will be equal to the friction force provided by the rear wheels

let the friction force on a single rear wheel be 'f'

thus,

2f = 1000 N

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f = 500 N

5 0
4 years ago
A soil weighs 2,520 lbs/CY in its in situ condition, 1,970 lb/CY in its loose condition after excavation, and 3,025 lbs/CY in an
azamat

Answer:

load factor = 0.782

Shrink Factor = 0.833

no of truck is  62500

Explanation:

given data

soil weighs in situ condition  =  2,520 lbs/CY

soil weighs in loose condition  =  1,970 lb/CY

soil weighs in embanked state = 3,025 lbs/CY

average volume = 16 LCY

soil from a borrow pit = 1 million CCY

solution

first we get here Load Factor that is express as

load factor = \frac{1,970}{2550}

load factor = 0.782

and Shrink Factor will be as

Shrink Factor = \frac{2520}{3025}

Shrink Factor = 0.833

and

no of truck will be

no of truck = \frac{1000000}{16}

no of truck is  62500

6 0
4 years ago
If a master cylinder piston applies pressure to a brak piston that has twice as much square area what will be the force from the
sp2606 [1]

Explanation:

Pressure = force/area

Pressure stays the same.

If the area is doubled the force is doubled.

5 0
4 years ago
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