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Leokris [45]
3 years ago
6

For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halv

ed
Physics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer:

Following are the responses to these question:

Explanation:

Since the max^{m} is the current of ckt which depend on the reactance which   inductor that also enables the ckt and inductor resistance (X_L) for capacities

\to X_{C}=\frac{1}{W L}

for

\to X_{L}=wL

When w \longrightarrow 2w

L\longrightarrow \frac{L}{2}

then

\to X_{L}=2 w \times \frac{L}{2}=wL

 therefore, X_{L} remains at the same so, the maximum current remains the in same ckt.

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Explanation:

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NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp
IRINA_888 [86]

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supply storage area of the lunar outpost where gravity is 1.63m/s/s can only support 1 x 10 over 5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost?

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601000 N

Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

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Acceleration due to gravity on the earth surface = 9.8m/s²

Maximum weight of supplies as measured on EARTH :

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3 0
3 years ago
Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
GREYUIT [131]

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

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1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed  of 39.2 m/s?

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3 years ago
Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?
e-lub [12.9K]
  • Distance=2.5m
  • Time=9.1s

Average Velocity=Total Distance/Total Time

\\ \sf\longmapsto \dfrac{2.5}{9.1}

\\ \sf\longmapsto 0.3m/s

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3 years ago
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