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3 years ago

Where in nature would we find pure sand that does not contain smaller or larger particles?

Chemistry

1 answer:

sineoko [7]3 years ago

5 0

Explanation:

Sand is a common material found on beaches, deserts, stream banks, and other landscapes worldwide. In the mind of most people, sand is a white or tan, fine-grained, granular material. However, sand is much more diverse - even beyond the pink sand beaches of Bermuda or the black sand beaches of Hawaii.

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How many protons, neutrons, and electrons are contained in uranium-238?

monitta

It has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons.

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3 years ago

How many moles of He are in 16 g of the element? 1.0 mol 4.0 mol 8.0 mol 16 mol

Lady bird [3.3K]

Answer: 4 Mole

Explanation:

16/4 = 4

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3 years ago

How do atoms form a new substance?

lubasha [3.4K]

By sharing electeons with each other
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3 years ago

What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$

$4.2 + log\frac{0.05}{0.045} = 4.245$

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

$pH = pKa + log\frac{base}{acid}$

$4.245 = 3.75 + log\frac{base}{acid}$

$log\frac{base}{acid} = 0.5$

$\frac{base}{acid} = 3.162$

Now we must solve the equation above. This will be done using the following values

$\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L$

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

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3 0

1 year ago

Which of the following statements is true about rain falling from clouds?*

enot [183]

Answer:

Clouds are not made of liquid water but they hold liquid water, and when the pool of liquid water that fills the inside of clouds gets too large for the cloud to hold, the cloud releases the water as rain. ... Rain does not fall from clouds.

Explanation:

please give me brainlist and follow

8 0

3 years ago