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sdas [7]
3 years ago
11

Who was the American founder and leader of the Shakers in the 1770’s who advocated equality, individual responsibility, and peac

e?
Engineering
2 answers:
DaniilM [7]3 years ago
6 0

Answer: Ann Lee (1736-1784)

Explanation:

Semenov [28]3 years ago
6 0
The answer is Ann lee
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Need answers for these please ​
Step2247 [10]

Answer:

Following are given the answers one-by-one with explanation:

(a) 8 records

As records are the horizontal rows of data and we have 8 of them.

(b) 5 fields

As fields are vertical columns of data and we have 5 of them.

(c)E3000

As by sorting Makers_names in ascending order the last one would be Rany and by sorting Processor_type we have two option with Rany that are B1500 and E3000. We can see that E3000 will come at the end.

(d) Computer_type

As only two choices (Laptop and PC )  are being used under the column computer_type so it can be amended to contain Boolean data.

(e) format check

This will check that the field should contain one alphabet (capital letter) followed by 4 digits each.

i hope it will help you!

7 0
3 years ago
5. A non-cold-worked brass specimen of average grain size 0.01 mm has a yield strength of 150 MPa. Estimate the yield strength o
Papessa [141]

Answer:

97.17 MPa

Explanation:

Given:-

- The nominal strength of the grain, σ0  = 25 MPa

- The average grain size of the brass specimen, d* = 0.01 m

- The yield strength of the non-cold worked specimen, σy = 150 MPa

- Conditions of cold-working: T = 500°C , t = 1000 s

Find:-

Estimate the yield strength of this alloy after cold - working process

Solution:-

- The nominal strength of the grain is a function of yield strength of the material, grain yield factor ( Ky ) and the grain size.

- the following relation is used to determine the grain strength:

                             σ0  = σy  - ( Ky / √( d ) )

- We will use the above relation to determine the grain yield factor ( Ky ) for the alloy as follows. Note: here we will use the average value of grain size:

                            Ky = ( σy  - σy )*√( d* )

                            Ky = ( 150 - 25 ) * √0.01

                            Ky = 12.5 MPa - √mm

- Now we will use the cold working conditions of T = 500 C and time of the process is t = 1000 s. We will look up the elongated size of the grain after the cold-working process in lieu with its yield factor ( Ky ). Use figure 7.25.

- The cold-worked grain size with the given conditions can be read off from the figure 7.25. The new size comes out to be d = 0.03 mm.

- We will again use the nominal grain strength relation expressed initially. And compute for the new yield strength of the cold-worked alloy.

                            σ0  = σy  - ( Ky / √( d ) )

                            σy = σ0 + ( Ky / √( d ) )

                            σy = 25MPa + ( 12.5 / √( 0.03 mm ) )

                            σy = 97.17 MPa

- We see that the yield strength of the alloy decreases after cold-working process. This happens because the cold working process leaves with inter-granular strain ( dislocation of planes ) in the material structure which results from the increase in grain size.

6 0
3 years ago
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields
vampirchik [111]

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen  L_o = 50 mm

The final gage length L_f = 71 mm

The area = 206 mm²

maximum load  =  162,699 N

To determine the percent elongation in %, we use the formula:

\%EL = \dfrac{L_f-L_o}{L_o}\times 100

\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100

\%EL = \dfrac{21 mm}{50 \ mm}\times 100

\%EL = 0.42 \times 100

\mathbf{\%EL = 42 \%}

The percent elongation in the length of the specimen is 42%

4 0
4 years ago
Some soil has a discharge rate of 0.1 L/s, an area of 11 m2, and a hydraulic head that is given empirically by the function H =
Artist 52 [7]

Answer:

3.03 * 10 ⁻⁴ m/s

Explanation:

see attached picture for explanation.

3 0
3 years ago
An electric sign takes 40A from a 240V supply. What current will it take if the voltage is raised to 300V. Help PLEASE!!!​
Sergeeva-Olga [200]

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3 0
3 years ago
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