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Liono4ka [1.6K]
3 years ago
13

What is the energy change when the temperature of 15.0 grams of solid silver is decreased from 37.3 °C to 20.5 °C ?

Engineering
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

Q=58.716 W

Explanation:

Given that

mass ,m  = 15 g

The decrease in the temperature ,ΔT = 37.3 - 20.5  °C

ΔT = 16.8°C

We know that specific heat of silver ,Cp = 0.233 J/g°C

The energy change of the silver  is given as

Q = m Cp ΔT

Now by putting the values we get

Q= 15 \times 0.233\times 16.8\ W

Q=58.716 W

Therefore the change in the energy will be 58.716 W.

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Air enters the combustor of a jet engine at p1=10 atm, T1=1000°R, and M1=0.2. Fuel is injected and burned, with a fuel/air mass
snow_lady [41]

Answer:

M2 = 0.06404

P2 = 2.273

T2 = 5806.45°R

Explanation:

Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.

Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,

To1 = (1.008)*(1000) = 1008 ºR

R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)

F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2

Table A.3 of steam table gives P/P* = 2.273,

T/T* = 0.2066,

To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =

F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit

5 0
3 years ago
A compound sliding miter saw can be used to make
Sunny_sXe [5.5K]

Answer:

D

Explanation:

3 0
2 years ago
What is Elon Musk mad about?
boyakko [2]

Answer:

Tesla CEO Elon Musk tweeted that the company's stock was too high, and it immediately dropped in value. The tweet may have violated a deal Musk made with the SEC about his tweets and Tesla. Musk also tweeted patriotic lyrics, said his girlfriend Grimes is mad at him, and noted that their child is due on Monday

6 0
3 years ago
Water enters a tank from two pipes, one with a flow rate of 0.3 kg/s and the other with a flow rate of 0.1 kg / s. The tank has
stiks02 [169]

Answer:

total amount of water after 2 min will be 84.4 kg/s

Explanation:

Given data:

one tank inflow = 0.1 kg/s

2nd tank inflow = 0.3 kg/s

3rd tank outflow = 0.03 kg/s

Total net inflow in tank is = 0.3 +0.1 =0.4 kg/s

From third point, outflow is 0.03 kg/s

Therefore, resultant in- flow = 0.4 - 0.03

Resultant inflow is  = 0.37 kg/s

Tank has initially 40 kg water

In 2 min ( 2*60 sec), total inflow in tank is 0.37*60*2 = 44.4 kg

So, total amount of water after 2 min will be = 40+44.4 = 84.4 kg

8 0
3 years ago
Write an ALP to separate odd and even numbers from an array of N numbers; arrange odd
Marta_Voda [28]

Below is the program to separate odd and even numbers                                  

<u>Explanation</u>:

<u>L1:</u>

         mov ah,00

         mov al,[BX]

         mov dl,al

         div dh

         cmp ah,00

         je EVEN1

         mov [DI],dl

         add OddAdd,dl

         INC DI

         INC BX

         Loop L1

         jmp CAL

    <u>EVEN1:</u>

         mov [SI],dl

         add Even Add,dl

         INC SI

         INC BX

         Loop L1

    <u>CAL:   </u>  

         mov ax,0000

         mov bx,0000

         mov al,OddAdd

         mov bl,EvenAdd

         MOV  ax,4C00h

         int 21h

end

The above program separates odd and even numbers from the array using 8086 microprocessor. It has odd numbers in 2000h and even numbers in 3000h.

6 0
3 years ago
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