Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s
Answer:
True
Explanation:
If it weren't from a 90 degree angle then the circle would be a bit more oval shaped
Answer:
51.85m/s
Explanation:
Given parameters:
Mass of ball = 0.0459kg
Force = 2380N
Time taken = 0.001s
Unknown:
Speed of the ball afterwards = ?
Solution:
To solve this problem, we use Newton's second law of motion:
F = m x
F is the force
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
2380 = 0.0459 x
0.0459v = 2.38
v = 51.85m/s
Answer:
a)
, b)
, c)
, d) 
Explanation:
a) The angular velocity of the turntable after
.



b) The change in angular position is:



c) The tangential speed of a point on the rim of the turn-table:




d) The tangential and normal components of the acceleration of the turn-table:



![a_{n} = (0.365\times 10^{-3}\,m)\cdot \left[(0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )\right]^{2}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20%280.365%5Ctimes%2010%5E%7B-3%7D%5C%2Cm%29%5Ccdot%20%5Cleft%5B%280.421%5C%2C%5Cfrac%7Brev%7D%7Bs%7D%20%29%5Ccdot%20%28%5Cfrac%7B2%5Cpi%5C%2Crad%7D%7B1%5C%2Crev%7D%20%29%5Cright%5D%5E%7B2%7D)


The magnitude of the resultant acceleration is:

