All categories

1 year ago

I need help with this physics question ASAP. Thanks!

Physics

1 answer:

Ugo [173]1 year ago

5 0

From the calculation, the horizontal distance is 310 m.

<h3>What is the range of a projectile?</h3>

A projectile has to do with an object that is thrown at an angle. Now we know that the range of the projectile is given by the formula; R = u^2sin2θ/g

We we know that;

g = acceleration due to gravity

θ = angle

u = velocity

R = (60)^2 sin2(30)/10

R = 310 m

Learn more about projectile:brainly.com/question/11422992

#SPJ1

You might be interested in

In a controlled experiment, a scientist is studying how long it takes feathers of different sizes to fall to the ground. What is

nikdorinn [45]

Answer: independent variable: Size of the feather.

Explanation:

In an experiment, the manipulated/independent variable is, as the name implies, the variable that the scientist can control.

In this case, the scientist has only one variable that he can control at will, and this is the size of the feather (he can choose which feather he uses for the experiment)

So the manipulated variable will be the size of the feather.

And the dependent variable is the one that "answers" to the changes in the manipulated variable.

In this case, will be the time that it takes to the feather to fall to the ground.

5 0

3 years ago

When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to ________?

pav-90 [236]

When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to contract in size. The gravitational forces becomes strong and cause the star to reduce in size. as the star contracts, the temperature of the star also rises since the heat is distributed inside smaller Volume now.

4 0

3 years ago

Read 2 more answers

____ have more energy than ____. A. Radio waves; microwaves B. Ultraviolet rays; X-Rays C. Gamma rays; infrared rays D. Radio wa

Aloiza [94]

C. Gamma rays have more energy than infrared rays

6 0

3 years ago

You toss a 0.40-kg ball at 9.0 ms/ to a 14-kg dog standing on an iced-over pond. The dog catches the ball and begins to slide on

just olya [345]

Answer:

a) $v_{f}$ = 0.25 m / s b) u = 0.25 m / s

Explanation:

a) To solve this problem let's start with the conservation of the moment, for this we define a system formed by the ball plus the dog, in this case all the forces are internal and the moment is conserved

We will write the data

m₁ = 0.40 kg

v₁₀ = 9.0 m / s

m₂ = 14 kg

v₂₀ = 0

Initial

po = m₁ v₁₀

Final

$p_{f}$ = (m₁ + m₂) vf

po = pf

m₁ v₁₀ = (m₁ + m₂) $v_{f}$

$v_{f}$ = v₁₀ m₁ / (m₁ + m₂)

$v_{f}$ = 9.0 (0.40 / (0.40 +14)

$v_{f}$ = 0.25 m / s

b) This is the reference frame of the center of mass of the system in this case the speed of this frame is the speed of the center of mass

u = 0.25 m / s

In the direction of movement of the ball

c) Let's calculate the kinetic energy in both moments

Initial

K₀ = ½ m₁ v₁₀² +0

K₀ = ½ 0.40 9 2

K₀ = 16.2 J

Final

$K_{f}$ = ½ (m₁ + m₂) $v_{f}$ 2

$K_{f}$ = ½ (0.4 +14) 0.25 2

$K_{f}$ = 0.45 J

ΔK = K₀ - $K_{f}$

ΔK = 16.2-0.445

ΔK = 1575 J

These will transform internal system energy

d) In order to find the kinetic energy, we must first find the velocities of the individual in this reference system.

v₁₀’= v₁₀ -u

v₁₀’= 9 -.025

v₁₀‘= 8.75 m / s

v₂₀ ‘= v₂₀ -u

v₂₀‘= - 0.25 m / s

$v_{f}$ ‘= $v_{f}$ - u

$v_{f}$ = 0

Initial

K₀ = ½ m₁ v₁₀‘² + ½ m₂ v₂₀‘²

Ko = ½ 0.4 8.75² + ½ 14.0 0.25²

Ko = 15.31 + 0.4375

K o = 15.75 J

Final

$k_{f}$ = ½ (m₁ + m₂) vf’²

$k_{f}$ = 0

All initial kinetic energy is transformed into internal energy in this reference system

3 0

3 years ago

An aircraft has a mass of 3.30 x 105 kg. At a certain instant during its landing, its speed is 45.2 m/s. If the braking force is

melamori03 [73]

Ultraconservative the future and I have been working with the following questions.

8 0

3 years ago