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1 year ago

I need help with this physics question ASAP. Thanks!

Physics

1 answer:

Ugo [173]1 year ago

5 0

From the calculation, the horizontal distance is 310 m.

<h3>What is the range of a projectile?</h3>

A projectile has to do with an object that is thrown at an angle. Now we know that the range of the projectile is given by the formula; R = u^2sin2θ/g

We we know that;

g = acceleration due to gravity

θ = angle

u = velocity

R = (60)^2 sin2(30)/10

R = 310 m

Learn more about projectile:brainly.com/question/11422992

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Plz help me I’m a desperate little boy

Neporo4naja [7]

It is the first one. But if you have this question you are not a little boy

5 0

2 years ago

A baseball is hit at ground level. The ball reaches its maximum height above ground level 3.0 s after being hit. Then 2.5 s afte

vaieri [72.5K]

Answer:

Part a)

$H = 44.1 m$

Part b)

$y = 13.48 m$

Part c)

$d = 8.86 m$

Explanation:

Part a)

As we know that ball will reach at maximum height at

t = 3 s

now we will have

$t = \frac{v sin\theta}{g}$

now we have

$3 = \frac{vsin\theta}{9.8}$

$v sin\theta = 29.4 m/s$

Now maximum height above ground is given as

$H = \frac{v^2sin^2\theta}{2g}$

$H = \frac{29.4^2}{2(9.8)}$

$H = 44.1 m$

Part b)

Height of the fence is given as

$y = (vsin\theta) t - \frac{1}{2}gt^2$

$y = (29.4)(5.5) - \frac{1}{2}(9.8)(5.5^2)$

$y = 13.48 m$

Part c)

As we know that its horizontal distance moved by the ball in 5.5 s is given as

$x = v_x t$

$97.5 = v_x (5.5)$

$v_x = 17.72 m/s$

now total time of flight is given as

$T = 3 + 3 = 6 s$

so range is given as

$R = v_x T$

$R = (17.72)(6)$

$R = 106.4 m$

so the distance from the fence is given as

$d = 106.4 - 97.5$

$d = 8.86 m$

7 0

3 years ago

Explain how a form of<br> energy is used in daily life

hram777 [196]

Answer:

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