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2 years ago

The sum of the measures of ∠QRT and ∠TRS is 180∘.

Mathematics

2 answers:

Harman [31]2 years ago

5 0

Answer:

90° i think..........

Degger [83]2 years ago

3 0

Pretty sure it’s 90°

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What is x ? please help :)

bekas [8.4K]

Answer:

x =12

Step-by-step explanation:

The two angles are complementary, so the add to 90 degrees

5x+1/2x +24 = 90

Combine like terms

5 1/2 x +24 = 90

Subtract 24 from each side

5 1/2 x = 90-24

Change the mixed number to an improper fraction

11/2 x = 66

Multiply by the reciprocal 2/11 on each side

2/11 *11/2 x = 66*2/11

x = 6*2

x =12

3 0

3 years ago

If y varies inversely as x and y=3 when x=4, then y=12 when x=15 <br><br> True or false ?

Elden [556K]

y=12 is false answer.

8 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

PLZZZZ HELPPPPP BRAINLIEST REWARDD

Wewaii [24]

Answer:

1) Growth

2) y = 3

Explanation:

1) y = a*b^x

y = 3 + 2^x

2 > 1, so it's growth

7 0

2 years ago

Show me how to Graph y = 3x + 2

melisa1 [442]

This what it should look like. did you need the steps or no ?

4 0

3 years ago