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mafiozo [28]
3 years ago
12

It is known that a shark can travel at a speed of 17 m/s. How far can a shark go in 8 seconds? (please show steps to how you got

the answer)
Physics
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

136 meters.

Explanation: If it can go 17 meters a second, then after 8 seconds, it will go 136 meters. Multiple 17 by 8 to get your answer.

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A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 13.0 cm , giving it a ch
Leokris [45]

a) Electric field inside the paint layer: zero

b) Electric field just outside the paint layer: -3.62\cdot 10^7 N/C

c) Electric field 8.00 cm outside the paint layer: -7.27\cdot 10^7 N/C

Explanation:

a)

We can find the electric field inside the paint layer by applying Gauss Law: the total flux of the electric field through a gaussian surface is equal to the charge contained within the surface divided by the vacuum permittivity, mathematically:

\int EdS = \frac{q}{\epsilon_0}

where

E is the electric field

dS is the element of surface

q is the charge within the gaussian surface

\epsilon_0 = 8.85\cdot 10^{-12}F/m is the vacuum permittivity

Here we want to find the electric field just inside the paint layer, so we take a sphere of radius r as Gaussian surface, where

R = 6.5 cm = 0.065 m is the radius of the plastic sphere (half the diameter)

By taking the sphere of radius r, we note that the net charge inside this sphere is zero, therefore

q=0

So we have

\int E dS=0

which means that the electric field inside the paint layer is zero.

b)

Now we want to find the electric field just outside the paint layer: therefore, we take a Gaussian sphere of radius

r=R=0.065 m

The area of the surface is

A=4\pi R^2

And since the electric field is perpendicular to the surface at any point, Gauss Law becomes

E\cdot 4\pi R^2 = \frac{q}{\epsilon_0}

The charge included within the sphere in this case is the charge on the paint layer, therefore

q=-17.0\mu C=-17.0\cdot 10^{-6}C

So, the electric field is:

E=\frac{q}{4\pi \epsilon_0 R^2}=\frac{-17.0\cdot 10^{-6}}{4\pi(8.85\cdot 10^{-12})(0.065)^2}=-3.62\cdot 10^7 N/C

where the negative sign means the direction of the field is inward, since the charge is negative.

c)

Here we want to calculate the electric field 8.00 cm outside the surface of the paint layer.

Therefore, we have to take a Gaussian sphere of radius:

r=8.00 cm + R = 8.00 + 6.50 = 14.5 cm = 0.145 m

Gauss theorem this time becomes

E\cdot 4\pi r^2 = \frac{q}{\epsilon_0}

And the charge included within the sphere is again the charge on the paint layer,

q=-17.0\mu C=-17.0\cdot 10^{-6}C

Therefore, the electric field is

E=\frac{q}{4\pi \epsilon_0 r^2}=\frac{-17.0\cdot 10^{-6}}{4\pi(8.85\cdot 10^{-12})(0.145)^2}=-7.27\cdot 10^7 N/C

Learn more about electric field:

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brainly.com/question/4273177

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5 0
3 years ago
Consider a hot-air balloon. The deflated balloon, gondola, and two passengers have a combined mass of 315 kg. When inflated, the
vladimir2022 [97]

This will help you.

3 0
3 years ago
a ball drops some distance and loses 30 j of gravitational potential energy. do not ignore air resistance. how much kinetic ener
aniked [119]

Thus, more than 30 J of potential energy can be loosed by the ball. Thus, the gravitational potential energy of the ball is more than 30 J.

If there is no air resistance, the ball's potential energy is entirely transformed into kinetic energy. When air resistance is taken into account, a portion of the potential energy is used to overcome it. Thus, AU > AKE. In the current scenario, a ball gains 30 J of kinetic energy while falling and is treated as encountering air resistance. The energy that an object retains due to its position in relation to other objects, internal stresses, electric charge, or other factors is known as potential energy in physics. The potential energy will be transformed into kinetic energy if the stones fall. High on the tree, branches have the potential to fall, which gives them energy. Chemical potential energy exists in the food we eat.

Learn more about potential energy here:

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5 0
11 months ago
Two people person A and person B lift the same amount of weight but person A lifts it in a shorter amount of time who has more p
const2013 [10]
Person A has more muscular strength then person B.  B has muscular endurance.
3 0
3 years ago
A 2.3 m -long wire carries a current of 8.6 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
Volgvan

Answer:

Explanation:

Given that :

The current I = 8.6 A

The length vector L = 2.3 m i

The force vector is = -2.0 j N

When L = 2.3 m i ; the

Force vector F = (2.0 i - 4.8 k) N

Compute the components of the magnetic field as follows:

F = I(L*B)

Replacing 8.6 A for I ; -2.0 j N for F & 2.3 m i for L

-2.0 j N = (8.6 A) (2.3 m i *(B_xi + B_yj+B_zk)

-2.0 j N = 19.78B_z \ and  \ 0 = 19.78B_y

B_z = -0.1011 T  \ and \ B_y = 0

However in y direction ; we have :

(2.0 i - 4.8 k) = 8,6 A (2.3 mi*(B_xi+B_yj+B_zk)

- 2.0 = 19.78 B_z \ and \ -4.8 = 19.78 B_x

B_z = -0.1011 T \ and \ B_x = -0.2427T

Hence, the component of magnetic field is as follows:

B_x = -.02427T \ ; B_y = 0 T \  ; B_z =  - 0.1011 T)

5 0
2 years ago
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