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alex41 [277]
3 years ago
13

g f, as a pioneer, you wished to warm your room by taking an object heated on top of a stove into it, which of the following 15

lb objects, each heated to 100 degrees celcius, would be the best choice and why. The specific heat capacity (in J/(g.K)) is given in parenthesis. Iron (0.450), copper (0.387), granite (0.79), gold (0.129), or water (4.18)
Physics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

Granite

Explanation:

The best choice would be granite.

This is because granite has the highest specific heat capacity of 0.79 J/(g.K) and would thus store more heat in it for the same mass and same temperature change as the other materials.

Since it contains more heat, it would be able to heat up the room to a higher temperature than the other materials.

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E = nhc/λ
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4 0
3 years ago
What would the final temperature be if 8.94 X 10 3 joules of heat were added to 454 grams of copper at 23.0 o C?
ozzi

Answer: 74.1^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=8.94\times 10^3 Joules

m= mass of copper = 454 g

c = specific heat capacity = 0.385J/g^0C

Initial temperature of the copper = T_i = 23.0°C

Final temperature of the water = T_f  = ?

Change in temperature ,\Delta T=T_f-T_i

Putting in the values, we get:

8.94\times 10^3=454\times 0.385\times (T_f-23.0)^0C

T_f=74.1^0C

The final temperature of copper will be 74.1^0C

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50N is your force and the acceleration is -9.8m/s^2 due to gravity. 

So, you just plug that in. 

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BUT you know that mass cannot be negative, so you just disregard the negative sign and the mass of the rock is 5.102 grams.
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3 years ago
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