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4 years ago

What equation is the relationship between wavelength and frequency?

1 answer:

7 0

That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave. The equation that relates wavelength and frequency for electromagnetic waves is: λν=c where λ is the wavelength, ν is the frequency and c is the speed of light.

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Two substances both exhibit hydrogen bonding. Substance A has a boiling point of 78.4ºC. Substance B has a boiling point of 100º

Feliz [49]

Answer:

The answer is C

Explanation:

Just took the test

6 0

2 years ago

Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.150 M sodium hydroxide with 0.150 M HBr(aq). (

Taya2010 [7]

Answer:

a) pH = 13.176

b) pH = 13

c) pH = 12.574

d) pH = 7.0

e) pH = 1.46

f) pH = 1.21

Explanation:

HBr + NaOH ↔ NaBr + H2O

∴ equivalent point:

⇒ mol acid = mol base

⇒ (Va)*(0.150mol/L) = (0.025L)*(0.150mol/L)

⇒ Va = 0.025 L

a) before addition acid:

NaOH → Na+ + OH-

⇒ C NaOH = 0.150 M

⇒ [ OH- ] = 0.150 M

⇒ pOH = - Log ( 0.150 )

⇒ pOH = 0.824

⇒ pH = 14 - pOH

⇒ pH = 13.176

b) after addition 5mL HBr:

⇒ C NaOH = (( 0.025)*(0.150) - (0.005)*(0.150)) / (0.025 + 0.005) = 0.1 M

⇒ C HBr = (0.005)*(0.150) / ( 0.03 ) = 0.025 M

⇒ [ OH- ] = 0.1 M

⇒ pOH = 1

⇒ pH = 13

c) after addition 15mL HBr:

⇒ C NaOH = ((0.025)*(0.150) - (0.015)*(0.150 ))/(0.04) = 0.0375 M

⇒ C HBr = ((0.015)*(0.150))/(0.04) = 0.0563 M

⇒ [ OH- ] = 0.0375 M

⇒ pOH = 1.426

⇒ pH = 12.574

d) after addition 25mL HBr:

equivalent point:

⇒ [ OH- ] = [ H3O+ ]

⇒ Kw = 1 E-14 = [ H3O+ ] * [ OH- ] = [ H3O+ ]²

⇒ [ H3O+ ] = 1 E-7

⇒ pH = 7.0

d) after addition 40mL HBr:

⇒ C HBr = ((0.04)*(0.150) - (0.025)*(0.150)) / (0.04 + 0.025) = 0.035 M

⇒ [ H3O+ ] = 0.035 M

⇒ pH = 1.46

d) after addition 60mL HBr:

⇒ C HBr = ((0.06)*(0.150) - (0.025)*(0.150)) / (0.06+0.025) = 0.062 M

⇒ [ H3O+ ] = 0.062 M

⇒ pH = 1.21

8 0

4 years ago

Read 2 more answers

K₂O(s) + H₂O (l)-> KOH(aq)

Ber [7]

Answer:

K20(s)+H2O(L) -> 2KOH(aq)

6 0

3 years ago

Questions to be ask for testing a starch

ddd [48]

I'm assuming you're asking how to test for a starch,

To do so you do this thing called the "Iodine Test"
The potassium iodide aqueous solution will form this complex with starch to form a purplish-blue color.

However, watch out for the pH as hydrolysis of starch could occur to prevent the test from working out-- and the temperature as the greater it is, the less intense the color is

8 0

3 years ago

Malic acid, C4H6O5, has been isolated from apples. Because this compound reacts with 2 molar equivalents of base, it is a dicarb

Flura [38]

Answer and explanation:

The attached figure shows five different structures for the chemical formula C4H5O5, but only one of these structures represent the malic acid.

Malic acid is a dicarboxylic acid, this means malic acid has two

-COOH groups. Also, malic acid is a secundary alcohol, which means it has a R2-C-OH group.

-Structure A has two carboxylic groups, but it doesn´t have a secundary alcohol.

-Structure B doesn´t have any caborxylic group.

-Structure C has two carboxylic groups and it is a secundary alcohol. Structure C is the Malic acid

4 0

3 years ago